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Flura [38]
1 year ago
15

Drag the labels onto the table to indicate when each statement Is true. Labels can be used once, more than once, or not at all.

1. Orange dye moves independently of purple dye. 2. Concentration gradients exist that drive diffusion of both dyes. 3. There is a net movement of orange dye from side A to side B. 4. Purple dye moves only from side B lo side A. 5. There is no net movement of purple dye.
Chemistry
1 answer:
liq [111]1 year ago
3 0

The labels the table to indicate when each statement Is true. Labels can be used once, more than once, or not at all, The orange dye moves independently of the purple dye. 2. Concentration gradients exist that drive diffusion of both dyes. : <u>free water, solute, free water, solute.</u>

In chemistry, attention is the abundance of a constituent divided by way of the total quantity of an aggregate. several types of mathematical descriptions may be prominent: mass concentration, molar concentration, range concentration, and quantity concentration.

it's miles the amount of solute dissolves in one hundred g solvent. If the attention of the answer is 20 %, we understand that there are 20 g solutes in one hundred g solution. instance: 10 g salt and 70 g water are mixed and the solution is ready. find awareness of the answer by means of percentage mass.

Learn more about concentration here:

brainly.com/question/26255204

#SPJ4

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Calculate how to prepare 250.00 ml of approximately 1.0 m hcl solution from the 2.5 m hcl solution. show your work.
Romashka-Z-Leto [24]
250.00 mL) x (1.0 M ) / (2.5 M) = 100 mL

So take 100 mL of 2.5 M HCl and dilute it to 250 mL.
5 0
4 years ago
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4. 200 mL of a 5.6M solution to BaCl_2 have 750 mL of water added to it. What is the new concentration?
IceJOKER [234]

Answer:

4. 1.18 mol·L⁻¹

14. See below.

Explanation:

4. Dilution calculation

V₁c₁ = V₂c₂

Data:

V₁ = 200 mL; c₁ = 5.6 mol·L⁻¹

V₂ = 950 mL; c₂ = ?

Calculation:

c₂ = c₁ × V₁/V₂

c₂ = 5.6 mol·L⁻¹ × (200/950) = 1.18 mol·L⁻¹

The new concentration is 1.18 mol·L⁻¹ .

14. Boyle's Law graphs

We can write Boyle's Law as

pV = k or p = k/V or V= k/p

p and V are inversely related.

(a) As pressure increases, volume decreases. Thus, a graph of V vs p is a hyperbola.

(b) p = k/V =k(1/V)

 1/V = (1/k)p

   y  =   m x  + 0

A graph of 1/V vs p is a straight line.

4 0
3 years ago
One mole of X contains how many molecules of X
mixer [17]

Answer:

The mole is represented by Avogadro's number, which is 6.022×1023 atoms or molecules per mol

Explanation:

5 0
3 years ago
What is the answer?
nevsk [136]

i believe that it is b

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May someone help me on this
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