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3 years ago

PLEASE HELP!! I GIVE BRAINLIEST

Chemistry

1 answer:

marshall27 [118]3 years ago

7 0

Answer:

1)C 2)B 3)D

Explanation:

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Given the following data in the Determination of Molar Mass of CO2 lab : Mass (before rxn): test tube HCl(aq) stir bar capsule 2

RSB [31]

Answer:

.259 g

Explanation:

PV = nRT

n = PV / RT

= .986 x 0.144 / .082 x 293.6

= .005897 moles

= .005897 x 44 g

= .259 g

3 0

3 years ago

Explain why elements with less protons require fewer neutrons to be stable compared to elements with more protons.

Solnce55 [7]

Answer:

The reason for this is because of the repulsive force between protons: The stronger the repulsion force, the more neutrons are needed to stabilize the nuclei.

Explanation:

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3 years ago

Calculate the mass of 4 moles of sodium hydroxide

harina [27]

Answer:

Mass = 160 g

Explanation:

Given data:

Number of moles of sodium hydroxide = 4 mol

Mass of sodium hydroxide = ?

Solution:

Formula:

Mass = number of moles × molar mass of sodium hydroxide

Molar mass of sodium hydroxide = 40 g/mol

Mass = 4 mol × 40 g/mol

Mass = 160 g

4 0

2 years ago

Which layer over time due to chemical and physical weathering leads to the other layers?

ivanzaharov [21]

Answer:

chemical weathering occurs on the surface of minerals, the water and acids that control chemical weathering require access to the surface. Physical weathering breaks the rock to provide that surface

7 0

2 years ago

The gas cyclobutane, C4H8(g), can be used in welding. When cyclobutane is burned in oxygen, the reaction is: C4H8(g) + 6 O2(g)4

Snowcat [4.5K]

Answer:

$\Delta H^o _{rxn} = -2568.9 \ kJ$

$H = 350 JK^{-1}$

$T_{max} = 32.4 ^o C$

Explanation:

From the question we are told that

The reaction of cyclobutane and oxygen is

$C_4H_8_{(g)} + 6 O_2_{(g)} \to 4 CO_2_{(g)} + 4 H_2O_{(g)}$

ΔH°f (kJ mol-1) : C4H8(g) = 27.7 ; CO2(g) = -393.5 ; H2O(g) = -241.8 ΔH° = kJ

Generally ΔH° for this reaction is mathematically represented as

$\Delta H^o _{rxn} = [[4 * \Delta H^o_f (CO_2_{(g)} ) + 4 * \Delta H^o_f(H_2O_{(g)} ] -[\Delta H^o_f (C_2H_6_{(g)} + 6 * \Delta H^o_f (O_2_{(g)}) ] ]$

=> $\Delta H^o _{rxn} = [[4 * (-393.5) + 4 * (-241.8) ] -[ 27.7 + 6 * 0]$

=> $\Delta H^o _{rxn} = -2568.9 \ kJ$

Generally the total heat capacity of 4 mol of CO2(g) and 4 mol of H2O(g), using CCO2(g) = 37.1 J K-1 mol-1 and CH2O(g) = 33.6 J K-1 mol-1. C = J K-1 is mathematically represented as

$H = [ 4 * C_{CO_2_{(g)}} + 6* C_{CH_2O_{(g)}}]$