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galben [10]
3 years ago
13

Stoichiometry (8A.S, 8B.R, 8G.S, 8H.S]:Question 4

Chemistry
1 answer:
Lostsunrise [7]3 years ago
4 0

Answer:

                    59.76 grams of Li₂O

Explanation:

To solve this problem we will first calculate the moles of Li₂O.                       One mole of given substance always contains 6.022 × 10²³ particles  which can be atoms, ions, molecules or formula units. This number is also called as Avogadro's Number.

The relation between Moles, Number of Particles and Avogadro's Number is given as,

                         Number of Moles  =  Number of Particles ÷ 6.022 × 10²³

Putting values,

                         Number of Moles  =  1.204 × 10²⁴ Particles ÷ 6.022 × 10²³

                         Number of Moles  =  2.0 Moles

Secondly, we will convert calculated moles to mass using following relationship.

                         Moles  =  Mass  /  M.Mass

Or,

                         Mass  =  Moles  ×  M.Mass

Putting values,

                         Mass  =  2.0 mol × 29.88 g/mol

                         Mass  =  59.76 grams of Li₂O

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Round the following answer correctly. 5.40m x 3.21m x 1.871m = 32.431914 m^3
Klio2033 [76]
The answer is 32.43 because when you round the number next to the hunthers place (witch in this problem would be the 1) has to be 5 or hight to raise the number to the left of it and if it is lower you just take the two number and that is your answer.
5 0
3 years ago
Alkenes are ______.<br><br> Saturated<br> Unreactive<br> Single bonds<br> Very reactive
Aleksandr [31]
Answer:
            Alkenes are <u>Very Reactive</u>.

Explanation:
                   Other options are incorrect because;

Saturated compounds are those hydrocarbons which contains only single bonds, while alkenes contain atleast one double bond.

Single bonds again stands for saturated compounds, hence it is false.

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5 0
4 years ago
4. Evaluate the information contained in this calculation and complete the
Neporo4naja [7]

Since you did not give a calculation, I will just give an example. Suppose that you are to burn 5 kg of methane (CH4) from 0 to 10°C. The specific heat capacity of methane is 4.475 kJ/kg-K.

H = mCpT

H = (5kg)( 4.475 kJ/kg-K)(10-0)

H = 223.75 kJ

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7 0
4 years ago
Calculate the mass percent (m/m) of a solution prepared by dissolving 45.09 g of NaCl in 174.9 g of H2O.
inysia [295]

Answer:

20.3 %  NaCl

Explanation:

Given data:

Mass of solute = 45.09 g

Mass of solvent = 174.9 g

Mass percent of solution = ?

Solution:

Mass of solution = 45.09 g + 174.9 g

Mass of solution = 220 g

The solute in 220 g is 45.09 g

220 g = 2.22 × 45.09

In 100 g solution amount of solute:

45.09 g/2.22 = 20.3 g

Thus m/m% = 20.3 %  NaCl

5 0
4 years ago
ASAP
Pie
Yes because the stigma rises above the gas I think that’s is it
6 0
3 years ago
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