Answer:
<u><em>note:</em></u>
<u><em>solution is attached</em></u>
A rectangular piece of paper has an area of 117 square inches and a perimeter of 44 inches. What are the dimensions of the paper
1 answer:
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Answer:
We can do it with envelopes with amounts $1,$2,$4,$8,$16,$32,$64,$128,$256 and $489
Step-by-step explanation:
- Observe that, in binary system, 1023=1111111111. That is, with 10 digits we can express up to number 1023.
This give us the idea to put in each envelope an amount of money equal to the positional value of each digit in the representation of 1023. That is, we will put the bills in envelopes with amounts of money equal to $1,$2,$4,$8,$16,$32,$64,$128,$256 and $512.
However, a little modification must be done, since we do not have $1023, only $1,000. To solve this, the last envelope should have $489 instead of 512.
Observe that:
- 1+2+4+8+16+32+64+128+256+489=1000
- Since each one of the first 9 envelopes represents a position in a binary system, we can represent every natural number from zero up to 511.
- If we want to give an amount "x" which is greater than $511, we can use our $489 envelope. Then we would just need to combine the other 9 to obtain x-489 dollars. Since
, by 2) we know that this would be possible.
Answer:
The number of children's tickets sold was 31 and the number of adult tickets sold was 2
Step-by-step explanation:
Let
x ---> the number of children's tickets sold
y ---> the number of adult tickets sold
we know that
the theater sold 33 tickets
so
-----> equation A
the theater made a total of $158.50
so
----> equation B
Solve the system by graphing
Remember that the solution of the system is the intersection point both graphs
using a graphing tool
The solution is the point (31,2)
see the attached figure
therefore
The number of children's tickets sold was 31 and the number of adult tickets sold was 2