y = Acos(Bx) + D;
D = 4, A = 2. Now T = 2π/B = 5π/8, B = 2π/(5π/8) = 16/5
WE get y = 2cos(16/5x) + 4
$11=2 hrs
2hrs=$11
+2(4hrs)=$22
+2(6hrs)=$33 hrs
so 6 hrs or 7 hours and some
minutes left
Answer:
Suppose a crew at an unloading dock can unload 3 trucks per hour and have already unloaded 17 trucks. Which equation can be used to model the number of trucks the crew unloads after h hours?
A. y = 3h = 17
B. y = 3h + 17
C. y = 17h – 3
<u>D. y = 17h + 3</u>
Step-by-step explanation:
Answer:
(X<-25) or -oo, -25
Step-by-step explanation:
because max is -25
V= 15 steps are down below
