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ELEN [110]
3 years ago
11

A female Drosophila with the mutant phenotype a is crossed to a male who has the mutant phenotype b. In the resulting F1 generat

ion all females are wild-type and all males have the a mutant phenotype. Based on these results, we can conclude that the mode of inheritance of the phenotype of interest is:
A) autosomal for a and X-Linked for b
B) dominant for a and recessive for b
C) recessive for a and dominant for b
D) recessive for both a and b
E) X-linked for a and autosomal for B
Biology
1 answer:
Mrac [35]3 years ago
3 0

Answer:

The correct answer is option D.

Explanation:

This is an illustration of X-linked recessive inheritance. This is a result of the mutation of genes on X-chromosomes. As females carry two X chromosomes, one from each parent, there is less chance for a female to carry mutant copies on both the X-chromosomes.  

As males possess only one X-chromosomes, obtained from the female parent, one changed gene is adequate to result in a mutant phenotype. All the males exhibit a mutant phenotype as the male parent cannot transfer the X-linked traits to the progeny.  

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Answer:

See the answer below

Explanation:

From the illustration of the experiment, the question that Carson can best answer  is that<em> "Do bananas develop more brown spots if they are kept in bags with holes  compared to bags without holes?"</em>

The independent variable in the experiment is the hole poked in the bags while the dependent variable is the number of brown spots on each banana. The difference between the subjects is the hole poked in the bags, hence, any difference in the number of brown spots between bananas in the bags with holes and those in the bags without holes can be attributed to the hole poked in the bags.

<u>Therefore, the question that can be answered from the experiment is to see if poking holes in bags make bananas to develop more brown spots compared to bags without holes. </u>

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