Answer:
First term = -41.
Common difference = -15.
Step-by-step explanation:
nth term: an = a1 + (n - 1)d where a = first term and d = the common difference.
-671 = a1 + (43 - 1)d
-806 = a1 +(52 - 1)d
-671 = a1 + 42d
-806 = a1 + 51d
Subtracting ( to eliminate a1):
-671 - (-806) = 42d - 51d
-9d = 135
d = -15
Substitute for d in the first equation:
-671 = a1 + 42*-15
-671 = a1 - 630
a1 = -671 + 630 = -41.
Answer:
The height of the water = 6.2 in. to the nearest tenth
Step-by-step explanation:
∵ The rate of flows of water into the tank = 8000 in.³/min.
∴ The volume of the water in the tank after 10 min. = 8000 × 10 = 80000 in.³
∵ The water take the shape of the tank
∴ The height of the water = volume of water ÷ Area of the base of the tank
∵ The tank is cylinder with diameter 128 in. and height 72 in.
∴ The area of the base of the tank = π(128/2)²
∴ The height of the water = 
∴ The height of the water = 6.2 in. to the nearest tenth
Answer:
x = 7.39
Step-by-step explanation:
log(x)²=(logx)², find the value of x
log x² = log x * log x
2log x = log x * log x
2 = log x
Take the exponent pf both sides
e² = e^logx
e² = x
x = e²
x = 7.39
Answer:
142.932
Step-by-step explanation:
given that in triangle ABC, AC =24
Angle A = 30 and Angle B =45
If we draw altitude from C, we get
h = 24sin 30 = 12
Since BC = h (45, 45,90 triangle)
BC=12
By sine formula for triangle

Area of triangle
= 
Answer:
25 ft
Step-by-step explanation:
The area of this landing pad is 1,962.5 ft², which equals πr².
We solve this equation for r²:
1962.5 ft²
r² = ----------------- = 625 ft²
3.14
Taking the square root of both sides, we get:
r = √(625 ft²) = 25 ft
The radius is 25 ft.