Ask question

Ask question

All categories

3 years ago

8

Y and x have a proportional relationship, and y = 9 when x = 2. What is the value of y when x = 3?

2 answers:

Illusion [34]3 years ago

5 0

Correct formula is y = kx, where k is the "constant of proportionality."

If y = 9 when x = 2, then 9 = k(2), or k = 9/2.

Then y = (9/2)x.

If x = 3, y = (9/2)(3) = 27/2 (answer)

KIM [24]3 years ago

4 0

Lol the answer is 27/2
k12 right

You might be interested in

A mechanic charges $330 for 6 hours of labor.

kompoz [17]

For 6 hours charges $330

for 9 hours charges x
---------------------------------

x = 9*330/6 = 495 so choice C. is right

5 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

2 years ago

What is the angle in a triangle that is part of a linear pair? i will give 15 points im desperate

gogolik [260]

Answer: Linear pairs of angles add up to 180 degrees. A+B=180

Step-by-step explanation: A linear pair of angles is formed when two lines intersect. Two angles are said to be linear if they are adjacent angles formed by two intersecting lines. The measure of a straight angle is 180 degrees, so a linear pair of angles must add up to 180 degrees

7 0

3 years ago

Plz help me, first one who helps will get a BRAINLIEST.

Gnom [1K]

Answer: 1. 1,0 2. -1,9 3.-20

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

What is the volume of metal in the pipe? Use 3.14 for a and

aleksandr82 [10.1K]

I need another number for this problem to answer

4 0

3 years ago

Read 2 more answers