The result of simplifying the expression (x²/x⁻¹¹)¹/₃ using the exponent rules is ![\sqrt[3]{}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%7D)
(x¹³)
To solve this exercise we have to resolve algebraic operations following the exponent rules.
(x²/x⁻¹¹)¹/₃
Using the quotient rule that indicates that: the exponent result will be the subtraction of these exponents, we have:
(x⁽²⁻⁽⁻¹¹⁾)¹/₃
(x⁽²⁺¹¹⁾)¹/₃
(x¹³)¹/₃
Using the power of a power rule that indicates that: the exponent result will be the multiplication of these powers, we have:
x⁽¹³*¹/₃⁾
x⁽¹³/₃⁾
As we have a fractional exponent, you must convert the exponent to root:
(x¹³)
<h3>What is an exponent?</h3>
In mathematics an exponent is the number of time that a number, called (base) is multiplied by itself. It is also called, power or index.
Example: 3² = 3*3 = 9
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Measure of the angle m ∠ RQS = 58 ° for the given circle with arc RS subtending m ∠RPS=14 x + 46 ° at the center P and m ∠ RQS = 3 x + 43 ° at Q, on the circumference.
As given in the question,
Measure of the angle is given by :
m ∠ RPS=14 x + 46 °
m ∠ RQS=3 x + 43 °
m ∠ RPS = twice m ∠RQS (angle subtended at center of the circle)
14 x +46 =2(3 x + 43)
⇒ 14x + 46 = 6x +86
⇒ 14x-6x=86-46
⇒8x=40
⇒ x=5°
m ∠ RQS = (3 x + 43) °
=[3(5) + 43 ]°
= 58°
Therefore, measure of the angle in the given circle m ∠RQS is equal to the 58 °
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2.1+18.9
The answer is going to be 21 because 9+1=10, you then carry the 1 for 8 so it’s going to be 9+2 which equals to 11 now you carry the 1 to the 1 so it’ll be 2. Therefore it’s 21.0 or just cancel out the 0 and just leave it as 21.
The results of the composite functions are:
<h3>What are composite functions?</h3>
Composite functions are functions that are obtained by combining two or more functions together
Assume that:
Then the computation of the composite functions are as follows:
<h3>Function (f * g)(x)</h3>
<h3>Function f(g(x))</h3>
We have: 
This gives
So, we have:
<h3>Function g(f(x))</h3>
We have: 
This gives
So, we have:
Read more about composite functions at:
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It’s going to be negative infinitely, infinitely.
