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Rina8888 [55]
3 years ago
13

What is the common ratio of the geometric sequence below 10,15,22.5,33.75​

Mathematics
1 answer:
snow_lady [41]3 years ago
6 0

Answer:

You divide each member by the one before it

Explanation:

You'll find that the answer  r = 1.5  ( r  for ratio)

The first term is called  u∧0 = 10

So the<em>  n</em> th term is called  u <em>n </em>− 1  and it takes <em> n</em> − 1  multiplications to get there from u 0 , so:

<em>n </em>th term =  u n  − 1  = u 0 ×  r n − 1

Or, in your case: <em> n</em> th term  = u <em>n </em>− 1 = 10 × 1.5<em> n </em>− 1

you can check out this it has the same answer as me

https://socratic.org/questions/how-do-you-find-the-nth-term-rule-for-10-15-22-5-33-75-50-63

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Answer:

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Elimination:

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Read 2 more answers
C + 6 &gt; 5c - 2<br>solved and proof​
Elena L [17]

Hi there!  

»»————- ★ ————-««

I believe your answer is:  

c < 2

»»————- ★ ————-««  

Here’s why:  

⸻⸻⸻⸻

c+6>5c - 2\\--------------\\\\\rightarrow5c - 2< c + 6 \leftarrow \text{Notice how the sides are switched.}\\\\\rightarrow 5c - c -2 < c - c + 6\\\\\rightarrow 4c -2 < 6\\\\\rightarrow 4c - 2 + 2 < 6 + 2\\\\\rightarrow 4c  < 8\\\\\rightarrow \frac{4c

⸻⸻⸻⸻

»»————- ★ ————-««  

Hope this helps you. I apologize if it’s incorrect.  

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