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nikitadnepr [17]
3 years ago
7

PLEASE HELP ASAAAAPPPPPP

Mathematics
2 answers:
monitta3 years ago
4 0
The correct answer is A

7nadin3 [17]3 years ago
4 0
The answer is A hope it helps

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Five and one half of 2 and one third is what number?
labwork [276]

Given:

Five and one half of 2 and one third.

To find:

The number for the given statement.

Solution:

Five and one half = 5\dfrac{1}{2}

2 and one third = 2\dfrac{1}{3}

The given statement is five and one half of 2 and one third.

Here, the word "of" is used for multiplication.

So, the expression for the given statement is:

5\dfrac{1}{2}\times 2\dfrac{1}{3}

=\dfrac{10+1}{2}\times \dfrac{6+1}{3}

=\dfrac{11}{2}\times \dfrac{7}{3}

=\dfrac{77}{6}

Therefore, the required number is \dfrac{77}{6}.

8 0
3 years ago
Can someone help me please
Nitella [24]

Answer:

16 units

Step-by-step explanation:

The perimeter is the sum of the lengths

Add up the lengths as shown

3+2+1+2+3+1+1+3

16 units

4 0
3 years ago
At a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective pa
11Alexandr11 [23.1K]

Answer:

Probability that fewer than 2 of these parts are defective is 0.604.

Step-by-step explanation:

We are given that at a certain auto parts manufacturer, the Quality Control division has determined that one of the machines produces defective parts 19% of the time.

A random sample of 7 parts produced by this machine is chosen.

The above situation can be represented through Binomial distribution;

P(X=r) = \binom{n}{r}p^{r} (1-p)^{n-r} ; x = 0,1,2,3,.....

where, n = number of trials (samples) taken = 7 parts

            r = number of success = fewer than 2

           p = probability of success which in our question is % of defective

                 parts produced by one of the machine, i.e; 19%

<em>LET X = Number of parts that are defective</em>

<u>So, it means X ~ Binom(n = 7, p = 0.19)</u>

Now, probability that fewer than 2 of these parts are defective is given by = P(X < 2)

    P(X < 2) = P(X = 0) + P(X = 1)

                  =  \binom{7}{0}\times 0.19^{0} \times (1-0.19)^{7-0}+ \binom{7}{1}\times 0.19^{1} \times (1-0.19)^{7-1}

                  =  1 \times 1 \times 0.81^{7} +7 \times 01.9^{1} \times 0.81^{6}

                  =  <u>0.604</u>

<em>Therefore, the probability that fewer than 2 of these parts are defective is 0.604.</em>

8 0
3 years ago
HELP PLZ
koban [17]
Y = -1/2x + 4
x + 2y = -8

x + 2(-1/2x+4) = -8
x + -x + 8 = -8
8 = -8

There correct answer is "no solution"
6 0
3 years ago
Read 2 more answers
BRAINLIEST!!!!!!!!!!! FOR THE BIG BRAIN BIH
Ksju [112]

Answer:

the value of x n lengh of pq is 12.6

8 0
3 years ago
Read 2 more answers
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