Answer:
for the first pic
1=133
2=47
3=47
4=133
5=133
6=47
7=47
8=133
the next pic
2,3 is a corresponding angle
1,2 is a verticle angle
the third pic
1=153
2=27
Step-by-step explanation:
 
        
                    
             
        
        
        
Let's simplify step-by-step.<span><span><span><span>−12</span>−12</span>−<span>12x</span></span>+6</span><span>=<span><span><span><span><span><span>−12</span>+</span>−12</span>+</span>−<span>12x</span></span>+6</span></span>Combine Like Terms:<span>=<span><span><span><span>−12</span>+<span>−12</span></span>+<span>−<span>12x</span></span></span>+6</span></span><span>=<span><span>(<span>−<span>12x</span></span>)</span>+<span>(<span><span><span>−12</span>+<span>−12</span></span>+6</span>)</span></span></span><span>
=<span><span>−<span>12x</span></span>+<span>−<span>18</span></span></span></span>
        
                    
             
        
        
        
Answer:
volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a (  x + b )² dx
x + b )² dx
Step-by-step explanation:
Given the data in the question and as illustrated in the image below;
R is in the region first quadrant with vertices; 0(0,0), A(a,0) and B(0,b)
from the image;
the equation of AB will be;
y-b / b-0 = x-0 / 0-a
(y-b)(0-a) = (b-0)(x-0) 
0 - ay -0 + ba = bx - 0 - 0 + 0
-ay + ba = bx  
ay = -bx + ba
divide through by a
y =  x + ba/a
x + ba/a
y =  x + b
x + b 
so R is bounded by  y =  x + b and y =0, 0 ≤ x ≤ a
x + b and y =0, 0 ≤ x ≤ a
The volume of the solid revolving R about x axis is; 
dv = Area × thickness
= π( Radius)² dx
= π (  x + b )² dx
x + b )² dx
V = π ₀∫^a (  x + b )² dx
x + b )² dx
Therefore,  volume of the solid generated when region R is revolved about the x-axis is π ₀∫^a (  x + b )² dx
x + b )² dx
 
        
             
        
        
        
R^m ÷ r^n is equal to r^(m-n). 
For example, 2^5 <span>÷ 2^3 = 2^2.
</span>
Is that what you mean?