Answer:
<em>B. 86 degrees</em>
Step-by-step explanation:
Given the following angles:
m∠NOQ = 110
m∠NOP = 24
Using the addition postulate:
m∠NOQ = m∠NOP + m∠POQ
110 = 24 + m∠POQ
m∠POQ = 110 - 24
m∠POQ = 86
<em>Hence the measure of m∠POQ is 86 degrees</em>
Answer:
1.155
Step-by-step explanation:
Hello,
7) A∪C={1,2,3,4,5,7,9}
8) A∩B={2,4}
C'= complement of C ={2,4,6}
9) A∪B∩C'={1,2,3,4,6,8}∩{2,4,6}={2,4,6}
10) A∪(B∩C')={1,2,3,4}∩{2,4,6}={1,2,3,4,6}
Are you blind?
Answers: ∠a = 30° ; ∠b = 60° ; ∠c = 105<span>°.
</span>_____________________________________________
1) The measure of Angle a is 30°. (m∠a = 30°).
Proof: All vertical angles are congruent, and we are shown in the diagram that angle A — AND the angle labeled with the measurement of 30°— are vertical angles.
2) The measure of Angle b is 60°. (m∠b = 60<span>°).
Proof: All three angles of a triangle add up to 90 degrees. In the diagram, we can examine the triangle formed by Angle A, Angle B, and a 90</span>° angle. This is a right triangle, and the angle with 90∠ degrees is indicated as such (with the "square" symbol). So we know that one angle is 90°. We also know that m∠a = 30°. If there are three angles in a triangle, and all three angles must add up to 180°, and we know the measurements of two of the three angles, we can solve for the unknown measurement of the remaining angle, which in this case is: m∠b.
90° + 30° + m∠b = 180<span>° ;
</span>180° - (<span>90° + 30°) = m∠b ;
</span>180° - (120°) = m∠b = 60<span>°
</span>___________________________
Now we need to solve for the measure of Angle c (<span>m∠c).
___________________________________________
All angles on a straight line (or straight "line segment") are called "supplementary angles" and must add up to 180</span>°. As shown, Angle c is on a "straight line". The measurement of the remaining angle represented ("supplementary angle" to Angle c is 75° (shown on diagram). As such, the measure of "Angle C" (m∠c) = m∠c = 180° - 75° = 105°.
Answer:

Step-by-step explanation:

The applicable rules of exponents are ...
- (a^b)(a^c) = a^(b+c)
- a^-b = 1/a^b