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saul85 [17]
2 years ago
14

La

Mathematics
1 answer:
tatyana61 [14]2 years ago
6 0

Answer:

32 tablespoons

$2.8

Step-by-step explanation:

Problem 1:

A chef has 2 cups of vinegar and she knows that there are 8 fluid ounces in one cup.

So, in total in 2 cups of vinegar, there are (8×2) =16 fluid ounces of liquid.

Now, 2 tablespoons volume is there in 1 fluid ounce.

Therefore, in total in 2 cups of vinegar, there are (16×2) =32 tablespoons of volume. So, option A is correct. (Answer)

Problem 2:

In a market, 7 oranges are sold for $2.45.

So, in this market 8 oranges are sold for \frac{2.45*8}{7} =$2.8 (Answer) {By simple unitary method of calculation}

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andreyandreev [35.5K]

Answer: 24.2° SouthWest

<u>Step-by-step explanation:</u>

First step: DRAW A PICTURE of the vectors from head to tail <em>(see image)</em>

I created a perpendicular from the resultant vector to the vertex of the given vectors so I could use Pythagorean Theorem to find the length of the perpendicular. Then I used that value to find the angle of the plane.

<u>Perpendicular (x):</u>

 cos 35° = adjacent/hypotenuse

  cos 35° = x/160

→ x = 160 cos 35°

<u>Angle (θ):</u>

sin θ = opposite/hypotenuse

sin θ = x/320

sin θ = 160 cos 35°/320

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Direction is down (south) and left (west)

7 0
3 years ago
How many centimeters in 60 inches?
ivann1987 [24]
152.4cm. 2.54cm = 1in. 60in x (2.54cm/1in) = 152.4cm.
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3 years ago
In a simple random sample of 300 boards from this shipment, 12 fall outside these specifications. Calculate the lower confidence
Lyrx [107]

Answer:

The 95% confidence interval for the percentage of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

Step-by-step explanation:

In a random sample of 300 boards the number of boards that fall outside the specification is 12.

Compute the sample proportion of boards that fall outside the specification in this sample as follows:

\hat p =\frac{12}{300}=0.04

The (1 - <em>α</em>)% confidence interval for population proportion <em>p</em> is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The critical value of <em>z</em> for 95% confidence level is,

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use a <em>z</em>-table.

Compute the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification as follows:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.04\pm1.96\sqrt{\frac{0.04(1-0.04)}{300}}\\=0.04\pm0.022\\=(0.018, 0.062)\\\approx(1.8\%, 6.2\%)

Thus, the 95% confidence interval for the proportion of all boards in this shipment that fall outside the specification is (1.8%, 6.2%).

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3 years ago
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sergeinik [125]

Answer:

The value is 25 x 6y

Step-by-step explanation:

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