Answer:
2nd choice down
$929.84
Step-by-step explanation:
3.19*36=114.85
114.84+815=929.84
Answer:
y - 7 = -8(x - 1)
Step-by-step explanation:
We are provided with some information
We are given point (1,7)
Slope = -8
Using a point slope form formula
y - y_1 = m (x - x_1)
m = -8
y_1 = 7
x_1 = 1
Inserting the given values into the equation
y - y_1 = m ( x - x_1)
y - 7 = -8 ( x - 1) ( point slope form)
Don't confuse slope intercept form with point slope form
Slope intercept form
y = mx + C
y - point y
m - slope
x - point x
C - intercept
Point slope form
y - y_1 = m(x - x_1)
Answer:
Step-by-step explanation:
First let us consider how we calculate the mean test mark in the first place, we add up the individual test marks of the entire class to give the total test mark then we divide by the number of students. This means we need two pieces of information to calculate the boys' mean mark, the total boys' mark and the number of boys. We already know the number of boys but how do we work out the total boys' test mark? If we can work out the total class mark and total girls' mark we can find the total boys' mark by subtracting the total girls' mark from the total class mark. To do this we can work backwards to find the total mark for the whole class by taking the mean mark and multiplying it by the number of students, this gives us Total Class Mark = Mean Class Mark x Number of Students = 60 x 30 = 1800. We can do the same for the girls' mark giving us Total Girls' Mark = Mean Girls' Mark x Number of Girls = 54 x 20 = 1080. This then gives us the total boys mark as Total Boys' Mark = Total Class Mark - Total Girls' Mark = 1800 - 1080 = 720. Now we have everything we need to work out the boys' mean mark and we get Boys' Mean Mark = Total Boys' Mark/Number of Boys = 720/10 = 72.
1. A straight line segment can be drawn joining any two points.
2. Any straight line segment can be extended indefinitely in a straight line.
3. Given any straight line segment, a circle can be drawn having the segment as radius and one endpoint as center.
4. All right angles are congruent.
5. If two lines are drawn which intersect a third in such a way that the sum of the inner angles on one side is less than two right angles, then the two lines inevitably must intersect each other on that side if extended far enough. This postulate is equivalent to what is known as the parallel postulate.
Answer:
x = -75
Step-by-step explanation:
x/-5=15
x = 15 x -5
x = -75
