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Klio2033 [76]
4 years ago
15

Provide two examples of things that apply to both relative and absolute dating.

Chemistry
1 answer:
Paul [167]4 years ago
5 0
Relative dating 
<span>1) The law of superposition states that, in an undisturbed stratigraphic environment, the oldest layers of strata are beneath the younger ones. </span>

<span>2) The law of original horizontality states that layers, when originally deposited, are fairly horizontal; folds and tilted beds are consequences of deformation that post-dates deposits. </span>

<span>3) The law of original continuity states that sedimentary layers generally accumulate in continuous sheets. </span>

<span>4) The law of cross-cutting relations states that cutting features are younger than the cut strata. </span>

<span>5) The principle of baked contacts states that igneous intrusions metamorphose surrounding rock, and the metamorphosed rock is older than the intrusion. </span>

<span>6) The principle of inclusions states that, if a layer of sediment over an igneous layer includes pebbles of the igneous rock, then the sediment is younger. </span>

<span>Absolute dating </span>
<span>1) Radioactive isotopes are unstable and decay at a constant rate, allowing geochronologists to determine a numerical age. Radiocarbon dating is used to date organic remains. </span>

<span>2) Rate of tree growth, shell growth, and production of other organic material </span>

<span>3) Rate of snow accumulation, clastic sediment deposition, and chemical sediment precipitation</span>
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how much potassium bromide, in grams, should be added to water to prepare 0.50 of solution with molarity of 0.125M?
Flura [38]
Volume = 0.50 L

Molar mass  KBr = 119.002 g/mol

Molarity = 0.125 M

Mass ( KBr) = ?

 mass = molarity * molar mass * volume

mass = 0.125 * 119.002 * 0.50

mass = 7.437625 g of KBr

hope this helps!
5 0
3 years ago
C-12 and C-13 are naturally-occurring isotopes of the element carbon. C-12 occurs 98.88% of the time and C-13 occurs 1.108% of t
Veseljchak [2.6K]

Answer:

c) (12×0.9889) + (13×0.01108)

Explanation:

Given data:

Percentage of C-12 = 98.89%

Percentage of C-13 = 1.108%

Atomic mass = ?

Solution:

98.89/100 = 0.9889

1.108/ 100 = 0.01108

Atomic mass = (12×0.9889) + (13×0.01108)

Atomic mass = (11.8668 + 0.144034)

Atomic mass = 12.01084

6 0
4 years ago
Which of the following chemical formulas shows a covalent compound? A.CO2 B.MgO C. NaCl D.HBr
gogolik [260]
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