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BaLLatris [955]
2 years ago
13

The amount of water vapor in a given volume of air is ______________ .The amount of water vapor in the air at any one time depen

ds on ______________ . Warmer air holds ______________ water thancooler air. Clouds form when humidity is ______________ and thetemperature is ______________ . ______________ humidity is definedas the amount of water vapor in the air ______________ by the amountthat would have to be present in the same air to form a ______________ or condense on a surface. ______________ is related to the humidityof the previous day. The air temperature at which water vapor in the air ______________ onto cool surfaces is the dew point.
word bank
humidity
temperature
more
high
low
relative
divided
cloud
dew
condenses
pls hurry and you'll do gr8 on dis and I rlly need help on dis!
PLS :) I'm cheering 4 u, to help me for Brainliest :)
Chemistry
1 answer:
Lera25 [3.4K]2 years ago
3 0
1) humidity 2) temperature 3) more 4) high 5) low 6) relative 7) divided 8) cloud 9) dew 10) divided. i think this is correct
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What is a ‘control’ in an experiment?
tensa zangetsu [6.8K]

Answer:

The answer fo this is D because of the person controlling the outcome for both variables

3 0
2 years ago
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When 125 mL of 0.150 M Pb(NO3)2 is mixed with 145 mL of 0.200 M KBr, 4.92 g of PbBr2 is collected. Calculate the percent yield.
Semenov [28]

Answer:

Y = 92.5 %

Explanation:

Hello there!

In this case, since the reaction between lead (II) nitrate and potassium bromide is:

Pb(NO_3)_2+2KBr\rightarrow PbBr_2+2KNO_3

Exhibits a 1:2 mole ratio of the former to the later, we can calculate the moles of lead (II) bromide product to figure out the limiting reactant:

0.125L*0.150\frac{molPb(NO_3)_2}{L} *\frac{1molPbBr_2}{1molPb(NO_3)_2} =0.01875molPbBr_2\\\\0.145L*0.200\frac{molKBr}{L} *\frac{1molPbBr_2}{2molKBr} =0.0145molPbBr_2

Thus, the limiting reactant is the KBr as it yields the fewest moles of PbBr2 product. Afterwards, we calculate the mass of product by using its molar mass:

0.0145molPbBr_2*\frac{367.01gPbBr_2}{1molPbBr_2} =5.32gPbBr_2

And the resulting percent yield:

Y=\frac{4.92g}{5.32g} *100\%\\\\Y=92.5\%

Regards!

4 0
3 years ago
What is the first step of seafloor spreading?
drek231 [11]

Answer:

1. A long crack in the oceanic crust forms at a mid ocean ridge

Explanation:

7 0
2 years ago
How many moles are there in 8.94*10^24 atoms P?
IgorC [24]

Answer:

<h2>14.85 moles </h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.94 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\   = 14.850498

We have the final answer as

<h3>14.85 moles</h3>

Hope this helps you

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Answer:

As temperature increases, the molecules and atoms move faster.

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