Answer:
y=x+1.5
Step-by-step explanation:
Y is always 1.5 more than x.
Answer:
<u>Subtract 5 from input</u>.
Step-by-step explanation:
10-5=5
8-5=3
6-5=1
<u>N</u><u>o</u><u>t</u><u>e</u><u>:</u><u>i</u><u>f</u><u> </u><u>y</u><u>o</u><u>u</u><u> </u><u>n</u><u>e</u><u>e</u><u>d</u><u> </u><u>t</u><u>o</u><u> </u><u>a</u><u>s</u><u>k</u><u> </u><u>q</u><u>u</u><u>e</u><u>s</u><u>t</u><u>i</u><u>o</u><u>n</u><u> </u><u>l</u><u>e</u><u>t</u><u> </u><u>m</u><u>e</u><u> </u><u>k</u><u>n</u><u>o</u><u>w</u><u> </u><u>a</u><u>b</u><u>o</u><u>u</u><u>t</u><u> </u><u>i</u><u>t</u><u>.</u>
Here is the solution based on the given problem above.
Given: Area of the piece of paper = 84 square inches
Width = 10 1/2 or 10.5 inches long
? = length of the piece of paper
To find the area of an object, the formula would be A= L x W
Now, let's substitute the given values above
84in2 = L(10.5in)
Now, divide both sides with 10.5 and we get 8.
L = 8 inches.
Therefore, the length of the paper is 8 inches.
Hope this solution helps.
Answer:
Step-by-step explanation:
(a) Approximate the population standard deviation (?) with the sample standard deviation (s)
Approximate the standard normal distribution with the Student's t distribution
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(b) The degree of freedom =n-1=60-1=59
Given a=0.1, t(0.05, df=59) =1.67 (from student t table)
So the lower bound is
xbar -t*s/vn =41 -1.67*3/sqrt(60) =40.35
So the upper bound is
xbar +t*s/vn =41 +1.67*3/sqrt(60) =41.65