Answer:
Test statistic = - 0.851063
- 2.520463
Step-by-step explanation:
H0 : μ ≥ 15
H1 : μ < 15
Sample mean, xbar = 14.5
Sample standard deviation, s = 4.7
Sample size = 64
Teat statistic :
(xbar - μ) ÷ (s/√(n))
(14.5 - 15) ÷ (4.7/√(64))
= - 0.851063
The critical value at α = 0.05
Using the T - distribution :
Degree of freedom, df = 64 - 1 = 63
Tcritical(0.05, 63) = 1.6694
Test statistic - critical value
-0.851063 - 1.6694
= - 2.520463
Answer:
Radius = 8.575 cm
Step-by-step explanation:
Formula for volume of a pyramid is;
V_p = ½Ah
Where A is area of base and h is height
Also, formula for volume of cone is given as;
V_c = ⅓πr²h
Now, we are told that V_p = V_c and that h is the same for both shapes.
Thus ;
½Ah = ⅓πr²h
h will cancel out to give;
½A = ⅓πr²
Cross multiply to give;
3A/2π = r²
Base area of pyramid is given as 154 cm². Thus;
(3 × 154)/2π = r²
r = √((3 × 154)/2π
r = 8.575 cm
Answer:
Five million four thousand three hundred
Step-by-step explanation:
Answer:
<u>Entran 9 cuadrados en la hoja</u>
<u>Se puden hacer 10 tarejtas por que hay un cuadradro de 10*10 extra.</u>
Step-by-step explanation:
El area de la hoja sera:
Ahora el area de cada tarjeta es:

Para determinar cuantos tarjetas entran en la hoja debemos vidivir las aras encontradas arriba:
<u />
<u>Entonces entran 9 cuadrados en la hoja</u>
<u>Se puden hacer 10 tarejtas por que hay un cuadradro de 10*10 extra.</u>
<u />
Espero te haya sido de ayuda!