Answer:
Option A. the solution a = -4 is an extraneous solution.
Step-by-step explanation:
Lets solve the radical equation to get the potential solutions.
√(a + 5) = (a + 3)
By squaring terms on both the sides
[√(a + 5)]² = (a +3)²
(a + 5) = (a + 3)²
(a + 5) = a² + 6a + 9
0 = a² + 6a + 9 - a - 5
a² + 5a + 4 = 0
a² + 4a + a + 4 + 0
a(a + 4) + 1(a + 4) = 0
(a + 1)(a + 4) = 0
a = -1 or a = -4
Now if we put the value of a = - 4 in the radical equation then we get
√(-4 + 5) = (-4 + 3)
√1 = -1
1 = -1 ( Therefore a = -4 is not the solution)
Now by putting a = -1
√(-1 +5) = -1 + 3
√4 = 2
2 = 2 which shows the equal relation.
Therefore a = -4 is an extraneous solution.
Option A. is the correct option.
Answer:
yes, Tran is correct.
Step-by-step explanation:
−1/4x+ −7+9/4x+2x
(−1/4x+9/4x+2x)+(−7)
4x+−7
Hope it helps
There is 2 equation or 2 x if you prefer
1. X-4= 6. That is equal to 10 so x1=10
2. X-4= -6. That is equal to -2 so x2= -2
It would be irrational.
Reasoning:
A rational number is any number that can be expressed as a fraction of two integers provided that the denominator is not zero.
π is an irrational number because its approxiamation is is not the exact value of π. Additionally, we know that the quotient of irrational numbers can be rational or irrational. Here is the case where we have , an irrational number divided by a rational number giving a quotient that is irrational.
Answer: A; r = square root (S/4pi)
Step-by-step explanation:
1. Divide 4pi on both sides to get r^2 by itself so the left side becomes S/4pi (you do this because 4, pi, and r^2 are being multiplied together on the right side in the original equation so to cancel that out and get r by itself you do the opposite of multiplication)
The equation should now look like r^2 = S/4pi
2. Square root both sides including r to get rid of the r^2 so it becomes just r (also when you square root both sides, you square root all of S/4pi not just S or 4pi but the whole thing)
After you do that, you get r = square root (S/4pi) which is answer A
Hope this helps! :)