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BlackZzzverrR [31]
3 years ago
8

Base your answers to questions 66 through 68 on the information below.

Chemistry
1 answer:
Zinaida [17]3 years ago
5 0
Atoms are divisible and can be broken down into smaller particles. We know these particles as protons, neutrons and electrons.
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Which 3 characteristics are used to describe all waves, regardless of type? Check all that apply.
Dmitry [639]

Answer:

Frequency

Trough

Crest

Explanation:

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2 years ago
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What is a chromosome
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A chromosome is a tightly coiled X of genetic material that has genes on it.
Hope this helps!

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14. All the following are necessary parts of a neutralization reaction except A. an indicator. B. a salt. C. water. D. an acid.
ValentinkaMS [17]

The correct answer is <em>B. a Salt </em><em>because The reaction of an acid and a base is called a neutralization reaction because the properties of both the acid and base are diminished or neutralized when they react. A neutralization reaction is a reaction of an acid with a base in aqueous solution to produce water and a salt, as shown by the following equation:</em>

<em>acid + base → salt + water</em>

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<em>* Hopefully this helps:) Mark me the brainliest:) </em>

<em>∞ 234483279c20∞</em>

6 0
3 years ago
The chemical formula for table sugar is C12H11O22. What can you tell from this formula?
just olya [345]
I say the answer is The ratio of oxygen atoms to hydrogen atoms in a molecule of sugar is 2 to 1 
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3 years ago
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Calculate the freezing point of a solution containing 5.0 grams of KCl and 550.0 grams of water. The molal-freezing-point-depres
yulyashka [42]

<u>Answer:</u> The freezing point of solution is -0.454°C

<u>Explanation:</u>

Depression in freezing point is defined as the difference in the freezing point of pure solution and freezing point of solution.

The equation used to calculate depression in freezing point follows:

\Delta T_f=\text{Freezing point of pure solution}-\text{Freezing point of solution}

To calculate the depression in freezing point, we use the equation:

\Delta T_f=iK_fm

Or,

\text{Freezing point of pure solution}-\text{Freezing point of solution}=i\times K_f\times \frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

where,

Freezing point of pure solution = 0°C

i = Vant hoff factor = 2

K_f = molal freezing point elevation constant = 1.86°C/m

m_{solute} = Given mass of solute (KCl) = 5.0 g

M_{solute} = Molar mass of solute (KCl) = 74.55 g/mol

W_{solvent} = Mass of solvent (water) = 550.0 g

Putting values in above equation, we get:

0-\text{Freezing point of solution}=2\times 1.86^oC/m\times \frac{5\times 1000}{74.55g/mol\times 550}\\\\\text{Freezing point of solution}=-0.454^oC

Hence, the freezing point of solution is -0.454°C

3 0
3 years ago
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