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Softa [21]
2 years ago
7

What is the barometric trend of the weather data?

Chemistry
1 answer:
larisa86 [58]2 years ago
4 0

Answer:

the change of atmospheric pressure during the last few (generally three) hours before a regular observation.

Explanation:

Even small changes in barometric pressure can greatly impact the weather. The Weather Trend directional arrow icon, included on many AcuRite weather station products, will show one of the following three barometric pressure trend directions, indicating potential future weather conditions.

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6) Andy has left a bucket of smelly cheese porridge to cool down in the
natta225 [31]

Explanation:

the air particales are always moving so it also takes the smell of the chesse with it and sreads everywhere in the house.

7 0
3 years ago
How much energy is required to vaporize 155 g of butane at its boiling point? the heat of vaporization for butane is 23.1 kj/mol
netineya [11]

The energy required to vaporize 155 g of butane at its boiling point: 61,723 kJ

<h3>Further explanation</h3>

Enthalpy is the amount of system heat at constant pressure.

The enthalpy is symbolized by H, while the change in enthalpy is the difference between the final enthalpy and the initial enthalpy symbolized by ΔH.

\large{\boxed{\boxed{\bold{\Delta H=H_{End}-H_{First}}}}

Delta H reaction (ΔH) is the amount of heat change between the system and its environment

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)

The standard unit is kilojoules (kJ)

The enthalpy change symbol (ΔH) is usually written behind the reaction equation.

Change in Standard Evaporation Enthalpy (ΔH vap) is a change in enthalpy at the evaporation of 1 mol liquid phase to the gas phase at its boiling point and standard pressure.

Examples of water evaporation:

 H₂O (l) ---> H₂O (g); ΔH vap = + 44kJ

The enthalpy of evaporation is positive because its energy is needed to break the attraction between molecules in a liquid

  • 155 g of butane

relative molecular mass of butane (C₄H₁₀) = 4.12 + 10.1 = 58 gram / mol

tex]\large{\boxed{mole\:=\:\frac{grams}{relative\:molecular\:mass}}}[/tex]

\large mole\:=\:\large \frac{155}{58}

mole = 2,672

Since the heat of vaporization for butane is 23.1 kj / mol, the energy needed to evaporate 2,672 moles of butane is:

23.1 kJ / mol x 2,672 mol = 61,723 kJ

<h3>Learn more</h3>

the heat of vaporization

brainly.com/question/11475740

The latent heat of vaporization

brainly.com/question/10555500

brainly.com/question/4176497

Keywords: the heat of vaporization, butane, mole, gram, exothermic, endothermic

4 0
3 years ago
Read 2 more answers
What the Purpose of seeds
k0ka [10]

Answer:

The purpose of all seed is reproduction and is to grow a new plant, thus propagating the species.

5 0
3 years ago
What is the frequency of an electromagnetic wave that has a wavelength of 4.55x10-3m
djverab [1.8K]

Answer:

hnjilbglu

Explanation:

nbjl,bhuk

5 0
3 years ago
Un gas ocupa un volumen de 12 litros a una presión de 912 mm Hg. Si permanece constante la temperatura, ¿A qué presión el gas oc
adoni [48]

Answer:

The  pressure occupied is 1, 8 atm.

Explanation:

We use the Boyle´s Mariotte ´s law: for a given mass of gas at constant temperature, the pressure and volume vary inversely proportionally: P1xV1= P2xV2. The unit of pressure is converted to mmHg in atm.

760 mmHg----1 atm

912 mmHg---x= (912 mmHg x 1 atm)/760 mmHg=1,2 atm

P1xV1= P2xV2

P2=P1xV1/V2= 1,2 atm x 12 L/ 8L= <em>1, 8 atm</em>

7 0
3 years ago
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