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tia_tia [17]
3 years ago
7

If a compound contains an anion which is the conjugate base of a weak acid, the addition of hydronium ion solubility does what ?

Chemistry
1 answer:
wel3 years ago
3 0

Answer:

The addition of hydronium ion increases the solubility of the salt

Explanation:

When a weak acid, MA dissociates in an aqueous solution, the following products in equilibrium are obtained;

MA ----> M+ + A-

The anion which is a conjugate base will be removed from the solution with the addition of a hydronium ion from an acid: 2H3O+ + 2A- ----> 2HA + 2H20

This distorts the reaction equilibrium. According to Le Chatelier’s principle, more MA will dissolve until in order to restore the previous equilibrium of the reaction.

Therefore, an acidic pH increases the solubility of almost all sparingly soluble salts whose anion is the conjugate base of a weak acid.

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Why do the pH scale generally range from 0 to 14 in aqueous solution?
zalisa [80]

Answer:

In aqueous solution the pH scale varies from 0 to 14, which indicates this concentration of hydrogen. Solutions with pH less than 7 are acidic (the value of the exponent of the concentration is higher, because there are more ions in the solution) and alkaline (basic) those with a pH higher than 7. If the solvent is pure water, the pH = 7 indicates neutrality of the solution

Explanation:

PH is a measure of how acidic or basic a liquid is. Specifically, from a dissolution. The acidity of a solution is essentially due to the concentration of hydrogen ions dissolved in it. In reality, the ions are not found alone, but are in the form of hydronium ions consisting of one oxygen molecule and three positively charged hydrogen. PH precisely measures this concentration. And to do it, we can use simple and very visual methods.

5 0
3 years ago
IF UR GOOD AT CHEM PLZ ANSWER MY PREVIOUS QUESTIONS ON MY PROFILE, I NEED HELP!!
erastova [34]

Answer:

Ok, I'll try

Explanation:

7 0
2 years ago
5)
Kryger [21]

The empirical formula : C₁₂H₄F₇

The molecular formula : C₂₄H₈F₁₄

<h3>Further explanation</h3>

mol C (MW=12 g/mol)

\tt \dfrac{18.24}{12}=1.52

mol H(MW=1 g/mol) :

\tt \dfrac{0.51}{1}=0.51

mol F(MW=19 g/mol)

\tt \dfrac{16.91}{19}=0.89

mol ratio of C : H : O =1.52 : 0.51 : 0.89=3 : 1 : 1.75=12 : 4 : 7

Empirical formula : C₁₂H₄F₇

(Empirical formula)n=molecular formula

( C₁₂H₄F₇)n=562 g/mol

(12.12+4.1+7.19)n=562

(281)n=562⇒ n =2

Molecular formula : C₂₄H₈F₁₄

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Answer:

B. To Identify the half reactions for the equation

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In 1953, who devopled the model that is shown below
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What model? can you screenshot it or send a link?
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