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forsale [732]
3 years ago
12

Convert 6.75 atm to torr Hg (using dimensional analysis method)

Chemistry
1 answer:
Naily [24]3 years ago
5 0
Well, torr and Hg are different units, but they have the same conversiton with atm.  

The conversion for atm to torr or mmHg is 1 atm = 760 torr = 760 mmHg.

Because you have 6.75 atm you can find both the torr and mmHg.

To use dimensional analysis just make sure that you cancel out your units as you go.

6.75 atm * (760 torr / 1 atm) = 5130 torr or 5.13 x 10 to the -3 torr with significant figures.  

I hope this helped. 
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Which postulate of Dalton's atomic theory was later proven wrong?
ruslelena [56]

Answer:

Option c and d

Explanation:

John Dalton. In 1808, John Dalton proposed a theory known as Dalton’s Atomic Theory. The theory was published in a paper titled “A New Chemical Philosophy”. This theory was new to that era

The 5 postulates of Daltons' atomic theory are:

1. All the matters are made of atoms.

2. Atoms of different elements combine to form compounds

3. Compounds contain atoms in small whole-number ratios

4. Atoms can neither be created nor destroyed . (This was later proven wrong )

5. All atoms of an element are identical and have the same properties (This was later proven wrong as atoms of same element may be different in case of elements having isotopes )

Therefore, options c and d are the answer.

6 0
3 years ago
A monatomic ideal gas at a pressure of 1.00 atm expands adiabatically from an initial volume of 1.50 m3 to a final volume of 4.0
tamaranim1 [39]

The correct answer is 1atm.

<h3>What is Kinetic theory of gases?</h3>

A lot of the fundamental ideas of thermodynamics were established with the help of the kinetic theory of gases, a straightforward yet historically significant classical model of the thermodynamic behaviour of gases. According to the model, a gas is made up of numerous identical submicroscopic particles (atoms or molecules) that are all moving rapidly and randomly. It is considered that they are substantially smaller in size than the particle spacing on average. Random elastic collisions between the particles and with the container's walls occur between the particles. The simplest form of the model only takes into account the interactions within the ideal gas.

learn more about Kinetic theory of gases refer:

brainly.com/question/3924326

#SPJ4

7 0
1 year ago
Which statement correctly describes a chemical reaction?
Trava [24]
The correct answer is C
6 0
3 years ago
Which of the following statements explain why the van der Waals equation must be used to describe real gases? X. interactions be
8090 [49]

Answer:

Statements Y and Z.

Explanation:

The Van der Waals equation is the next one:

nRT = (P + \frac{an^{2}}{V^{2}})(V -nb) (1)

The ideal gas law is the following:

nRT = PV (2)

<em>where n: is the moles of the gas, R: is the gas constant, T: is the temperature, P: is the measured pressure, V: is the volume of the container, and a and b: are measured constants for a specific gas.  </em>

As we can see from equation (1), the Van der Waals equation introduces two terms that correct the P and the V of the ideal gas equation (2),<u> by the incorporation of the intermolecular interaction between the gases and the gases volume</u>. The term an²/V² corrects the P of the ideal gas equation since the measured pressure is decreased by the attraction forces between the gases. The term nb corrects the V of the ideal gas equation, <u>taking into account the volume occuppied by the gas in the total volume, which implies</u> a reduction of the total space available for the gas molecules.          

So, the correct statements are the Y and Z: the non-zero volumes of the gas particles effectively decrease the amount of "empty space" between them and the molecular attractions between gas particles decrease the pressure exerted by the gas.            

Have a nice day!

5 0
3 years ago
2KMnO4= K2MnO4+ MnO2+O2 how many grams of KMnO4 are required to produce 1.60 grams of O2
Sergeu [11.5K]

Answer: 15.8 g of KMnO_4 will be required to produce 1.60 grams of O_2

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} O_2=\frac{1.60g}{32g/mol}=0.05moles

2KMnO_4\rightarrow K_2MnO_4+MnO_2+O_2

According to stoichiometry :

As 1 mole of O_2 is given by = 2 moles of KMnO_4

Thus 0.05 moles of O_2 is given by =\frac{2}{1}\times 0.05=0.10moles  of KMnO_4

Mass of KMnO_4=moles\times {\text {Molar mass}}=0.10moles\times 158g/mol=15.8g

Thus 15.8 g of KMnO_4 will be required to produce 1.60 grams of O_2

5 0
3 years ago
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