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3 years ago

Convert 6.75 atm to torr Hg (using dimensional analysis method)

1 answer:

5 0

Well, torr and Hg are different units, but they have the same conversiton with atm.

The conversion for atm to torr or mmHg is 1 atm = 760 torr = 760 mmHg.

Because you have 6.75 atm you can find both the torr and mmHg.

To use dimensional analysis just make sure that you cancel out your units as you go.

6.75 atm * (760 torr / 1 atm) = 5130 torr or 5.13 x 10 to the -3 torr with significant figures.

I hope this helped.

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Answer:

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Explanation:

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In the article "A Sea of Garbage" what message is each cartoon trying to convey to readers? Do they succeed?

sertanlavr [38]

Answer:

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3 years ago

What is the total probability of finding a particle in a one-dimensional box in level n = 4 between x = 0 and x = L/8?

Lubov Fominskaja [6]

Answer:

P = 1/8

Explanation:

The wave function of a particle in a one-dimensional box is given by:

$\psi = \sqrt \frac{2}{L} sin(\frac{n \pi x}{L})$

Hence, the probability of finding the particle in the one-dimensional box is:

$P = \int_{x_{1}}^{x_{2}} \psi^{2} dx$

$P = \int_{x_{1}}^{x_{2}} (\sqrt \frac{2}{L} sin(\frac{n \pi x}{L}))^{2} dx$

$P = \frac{2}{L} \int_{x_{1}}^{x_{2}} (sin^{2}(\frac{n \pi x}{L}) dx$

Evaluating the above integral from x₁ = 0 to x₂ = L/8 and solving it, we have:

$P = \frac{2}{L} [\frac{L}{16} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})]$

$P = \frac{1}{8} (1 - 4\frac{sin(\frac{n \pi}{4})}{n \pi})$

Solving for n=4:

$P = \frac{1}{8} (1 - 4\frac{sin(\frac{4 \pi}{4})}{4 \pi})$

$P = \frac{1}{8} (1 - \frac{sin (\pi)}{\pi})$

$P = \frac{1}{8}$

I hope it helps you!

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