That's far more problems than I usually accept in a single question, but since you're new and obviously a beginner, I'll try to help.
<span>To Increase an amount by 7% what single multiplier would you use </span>
<span>We want 7% more than 100% of the amount, so the multiplier is </span>
<span>(100% + 7%) = 107% = 1.07 </span>
<span>[Remember that "percent" means "per hundred," so we divide a percentage by 100 to get the numerical equivalent.] </span>
<span>To Decrease an amount by 7% what single multiplier would you use </span>
<span>We want 7% less than 100% this time, so the multiplier is </span>
<span>(100% - 7%) = 93% = 0.93 </span>
<span>5 ÷ 0.1 </span>
<span>= 50 </span>
<span>(To One Decimal Place) (0.3 x 2.8)Squared </span>
<span>[Notation: around here we usually write "squared" as ^2, where the ^ is an exponentiation sign.] </span>
<span>(0.3 x 2.8)^2 = 0.84^2 = 0.7056 </span>
<span>which is 0.7 when rounded to one decimal place. </span>
<span>6.38 + 4.52 ÷ 4.71 +9.53 </span>
<span>= 6.38 + (4.52 ÷ 4.71) + 9.53 [assuming operations in the usual order] </span>
<span>= about 6.38 + 0.96 + 9.53 </span>
<span>= 16.87 </span>
<span>Expand and Simplify </span>
<span>(x + 2)(x + 3) </span>
<span>= x^2 + 2x + 3x + 6 </span>
<span>= x^2 + 5x + 6 </span>
<span>Expand and Simplify </span>
<span>(x + 2)(x - 3) </span>
<span>= x^2 + 2x - 3x - 6 </span>
<span>= x^2 - x - 6 </span>
<span>x + 1 < 5 </span>
<span>x < 4 [subtracting 1 from both sides] </span>
<span>Make n the subject of the formula.... M=3n </span>
<span>3n = M </span>
<span>n = M/3</span>
Answer:
1. 29.67°
2. 68.96°
3. 89.85°
Step-by-step explanation:
1. Reference angle = x
Opposite = 45 cm
Adjacent = 79 cm
Therefore:
(nearest hundredth)
2. Reference angle = B
Opposite = 14
Hypotenuse = 15
Therefore:
(nearest hundredth)
3. Reference angle = x
Adjacent = 238,900 mi
Hypotenuse = 92,955,807 mi
Therefore:
(nearest hundredth)
Solve both formulas to y=mx+b (slope intercept formula) where m=slope and b=y-intercept
y=-3/1x+-7
x-2y=-14
-2y=-14-x
y=7+1/2x
Start with the b variable so for problem 1 put a dot on 0,-7 and for problem 2 put a dot on 0,7
Then from -7 for problem 1 depending on whether the slope is negative or positive go down 3 and over right 1 therefore another point for problem one is marked, at 1,-10; for problem 2 up 1 and to the right 2; 2,8
For problem one connect the dots of 0,-7 and 1,-10
For problem two connect the dots of 0,7 and 2,8
Answer:
25,26,27,28,29
Step-by-step explanation:
2 6 10 14 18 22 26 30 and so on
