Answer:
270 anticlockwise
-90 clockwise
-450 clockwise
Step-by-step explanation:
The answer, going clockwise is -90. One leg of the angle is on the +x axis and the other is going down from the origin. The only other answer is 270 degrees. That angle is starting at the + x axis and goes anticlockwise. It has to travel to the dividing line between the 3rd and 4th quad.
-450 also works. Starting at 0 and going -360 clockwise leads you right back to the +x axis. -450 -(-360) leaves you with -90. Minus 90 degrees puts you on the line between the 3rd and 4th quadrant which is the same place 270 and - 90 will land.
Everything else takes you other places. 450 for example is the +y axis and that is related to 90 degrees not - 90.
Answer:

General Formulas and Concepts:
<u>Algebra I</u>
- Exponential Rule [Rewrite]:

<u>Calculus</u>
[Area] Limits of Riemann's Sums - Integrals
Integration Rule [Reverse Power Rule]:
Integration Rule [Fundamental Theorem of Calculus 1]: 
Step-by-step explanation:
<u>Step 1: Define</u>
<u />
<u />
<u />
<u>Step 2: Find Area</u>
- [Integral] Set up area:

- [Integral] Rewrite:

- [Integral] Reverse Power Rule:

- [Area] Fundamental Theorem of Calculus:

Topic: Calculus
Unit: Basic Integration/Riemann Sums
Book: College Calculus 10e
Answer:
any of the factors of a product considered in relation to a specific factor especially : a constant factor of a term as distinguished from a variable. 2a : a number that serves as a measure of some property or characteristic (as of a substance, device, or process) coefficient of expansion of a metal. b : measure
Step-by-step explanation:
Answer:
Step-by-step explanation:
Consider the given expression is
![\ln (x\sqrt[3]{x^2+1})](https://tex.z-dn.net/?f=%5Cln%20%28x%5Csqrt%5B3%5D%7Bx%5E2%2B1%7D%29)
We need to rewrite the expression as a sum,difference,or multiple of logarithms.
![[\because \sqrt[n]{x}=x^{\frac{1}{n}}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5Bn%5D%7Bx%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5D)
Using the properties of logarithm we get
![[\because \ln (ab)=\ln a+\ln b]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20%28ab%29%3D%5Cln%20a%2B%5Cln%20b%5D)
![[\because \ln (a^b)=b\ln a]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cln%20%28a%5Eb%29%3Db%5Cln%20a%5D)
Therefore, the simplified form of the given expression is
.