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geniusboy [140]
3 years ago
15

Given RS=TU prove RT=SU

Mathematics
1 answer:
kondaur [170]3 years ago
8 0

I did it on paper. Have a look.

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jackson is going to the movies. he has to pay $7 for his ticket and $2 for each box of candy he buys. write an expression that r
ruslelena [56]

If Jackson went to the movies and payed $7 initially for his ticket and then payed $2 for each box of candy that he buys, then the equation could look like this: y = 2x + 7, where y represents the total cost and x represents the number of boxes of candy Jackson buys.

6 0
3 years ago
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Suppose that the length of a side of a cube X is uniformly distributed in the interval 9
Nastasia [14]

Answer:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

Step-by-step explanation:

Given

9 < x < 10 --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

v = x^3

For a uniform distribution, we have:

x \to U(a,b)

and

f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.

9 < x < 10 implies that:

(a,b) = (9,10)

So, we have:

f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Solve

f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.

Recall that:

v = x^3

Make x the subject

x = v^\frac{1}{3}

So, the cumulative density is:

F(x) = P(x < v^\frac{1}{3})

f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right. becomes

f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.

The CDF is:

F(x) = \int\limits^{v^\frac{1}{3}}_9 1\  dx

Integrate

F(x) = [v]\limits^{v^\frac{1}{3}}_9

Expand

F(x) = v^\frac{1}{3} - 9

The density function of the volume F(v) is:

F(v) = F'(x)

Differentiate F(x) to give:

F(x) = v^\frac{1}{3} - 9

F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}

F'(x) = \frac{1}{3}v^{-\frac{2}{3}}

F(v) = \frac{1}{3}v^{-\frac{2}{3}}

So:

f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.

8 0
3 years ago
What is the area of triangle ABC?
Vanyuwa [196]
3

...................................................................................................................
6 0
3 years ago
Read 2 more answers
2) A product originally costs $125. If the product goes on sale for 20% off, and then goes on sale for an additional 30% off, wh
alukav5142 [94]
To do these, always convert the percents to decimals, so you can subtract it from 1. Remember, 1 is the whole. When you subtract the part that's taken off, you are left with what you have to pay. If you have 20% off of $100, then you are paying for 80% of $100. **of means to multiply** so you would multiply: 0.8X100, which would be $80.

First, multiply 125x0.8

Multiply that answer by 0.7

You should get B. $70

3) multiple 22.90x0.93

You should get D
7 0
3 years ago
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What is the value of g(f(-5))?
fredd [130]

Replace x in the equation for f(x) with -5:

|2x +9| = |2(-5) +9| = |-10 +9| = |-1| = 1

Now find x 1 and see where the graph of G(x) crosses the Y :

It crosses ay Y = 5

The answer is A. 5

8 0
3 years ago
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