The length of a rectangle is 3 cm greater than its width. the area of the rectangle is 180 cm². find the length and the width.

Mathematics

1 answer:

eimsori [14]4 years ago

5 0

Answer:

L=15 W=12 15*12 = 180

Step-by-step explanation:

W*L = area

W*(W+3) = 180

Do the distributive

W^+3 W-180=0

Find 2 numbers that when multiplied ,the result is -180

and when added the result is 3

- 12* 15 = -180

-12 +15 = 3

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The line segment joining the points ( 3,-4) and (1,2) is trisected at the points P and Q . If the coordinates of P and Q are (p

sdas [7]

Answer:

P = 7/3 and q = 0

Step-by-step explanation:

The given parameters are;

The endpoints of the segment are, (3, -4) and (1, 2)

The points that trisect the given points are P and Q with coordinates (p, -2) and (5/3, q) respectively

Therefore, we have;

The first point of the trisection cuts 1/3 of the length from one point and the second point of the trisection cuts 2/3 of the length from the same point

The coordinates of P or Q = (3 - (3 - 1)/3, -4 - (-4 - 2)/3) = (7/3 , -2)

Therefore, given that the y-coordinate value of the derived point coincides with the y-coordinate value of the point P, (p, -2) and there is only one point with x = -2 on the line, we have that the coordinate of the point P is (p, -2) = (7/3 , -2)

∴ P = 7/3

Similarly we have the second point of the trisection, Q, given as follows;

We are already given the x-coordinate value of the point Q as the 5/3 in (5/3, q)

Point Q = (5/3, q) = (3 - 2×(3 - 1)/3, -4 - 2×(-4 - 2)/3) = (5/3 , 0)

Point Q = (5/3, q) = (5/3 , 0)

∴ q = 0.

3 0

3 years ago

2(a-3)÷(a-4)(a-5)+a-1÷(3-a)(a-4)+a-2÷(5-a)(a-3) simplify.

Arlecino [84]

<u><em>I'm almost confident that I did this wrong, but i tried...</em></u>

Answer: