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MrMuchimi
2 years ago
9

What is the measure of ABD

Mathematics
1 answer:
Paladinen [302]2 years ago
7 0

Answer:

Where is the question?

Step-by-step explanation:

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An office manager reported that he spent $350 on gifts for employees. He said that $240 was spent on clothing with each man rece
Allushta [10]

Answer:

So I assume we are figuring out the number of men and women here, so:

m + 2w = 12

m = 12 - 2w

12 - 2w + 3w = 22

w = 10

m + 2w = 12

m + 2(10) = 12

m + 20 = 12

m = -8

8 0
3 years ago
Anthony went out to eat dinner, and the meal cost $50.00. If Anthony received a 15% discount, what was the total value of the di
jok3333 [9.3K]

Answer:

$7.5

Step-by-step explanation:

7 0
3 years ago
Can someone help me with this thanks ​
Ugo [173]

The length of the brace required is 4.3m

What is sine rule?

In a ΔABC a, b and c are the sides and A, B and C are angles then,

\frac{a}{SinA}=\frac{b}{sinB}=\frac{c}{sinC}

We can find the length, l as shown below:

Let AB=3m, BC=2m and AC=l

Let ∠A=25°

So, in ΔABC

\frac{BC}{sinA}=\frac{AB}{sinC}=\frac{AC}{SinB}

\frac{BC}{sinA}=\frac{AB}{sinC}

\frac{2}{sin25}=\frac{3}{sinC}

\angle{C}=sin^{-1}(\frac{3\times sin25}{2} )

∠C=39.34°

∠A+∠B+∠C=180°

∠B=180°-25°-39.34°

∠B=115.66°

\frac{BC}{sinA}=\frac{AC}{SinB}

\frac{2}{sin25}=\frac{l}{sin(115.66)}

l=\frac{2\times sin(115.66)}{sin25}

l=4.2659

Rounding to nearest tenth of meter.

l=4.3m

Hence, the length of the brace required is 4.3m

Learn more about Sine Rule here:

brainly.com/question/25852087

#SPJ1

8 0
2 years ago
What’s the value of Y?
Montano1993 [528]

Answer:

44

Step-by-step explanation:

if 88 is the right angle degree, that means the acute angle would be half of 88.

88÷2=44

7 0
3 years ago
A certain club has 20 members. What is the ratio of the number of 5-member committees that can be formed from the members of the
MissTica

Answer:

C

Step-by-step explanation:

This is a combination question.

In the first instance, we select 5 from 20 and in the second case , we select 4 from 20.

The total number of ways to solve the first instance is 20C5 = 15504 ways

The total number of ways to solve the second instance is 20C4 = 4,845

The ratio of the first to the second scenario is 15,504/4,845 = 3.2 = 16 to 5

8 0
3 years ago
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