You can only change one variable in an experiment true or false
1 answer:
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Answer:
E=1824.81 V/m
Explanation:
Given that
Voltage difference = 5 V
Distance ,D= 3 mm
θ = 24°
As we know that electric filed given as
Given that D is 24° with respect to the perpendicular to the electrodes.So we have to take cos component of D.
d= D cosθ
d= 3 cos24°
d = 2.74 mm
So
E=1824.81 V/m
The magnitude of the magnetic force on the proton is 1.25× 10—¹³ N.
Speed of the proton = 5.02 × 10 ⁶ m /a
Angel of between the velocity and the magnetic force = 60 °
The magnitude of magnetic field B = 0.180 T
The magnitude of the magnetic force on the proton is,
Therefore, the magnitude of the magnetic force on the proton is 1.25× 10—¹³ N.
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Answer:
W =1562.53 N
Explanation:
It is given that,
Radius of the aluminium ball, r = 24 cm = 0.24 m
The density of Aluminium,
We need to find the thrust and the force. The mass of the liquid displaced is given by :
V is volume
Weight of the displaced liquid
W = mg
So,
So, the thrust and the force is 1562.53 N.