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ycow [4]
4 years ago
12

Which of the following examples describes an increase in potential energy?

Physics
2 answers:
kari74 [83]4 years ago
8 0

Answer: D.  a paint can being carried up a ladder

Explanation: Potential energy is the energy possessed by an object by virtue of its height.

P.E=m\times g\times h

m= mass

g = acceleration due to gravity

h = height

Thus Potential energy is directly proportional to the height of the body. The greater the height, greater is the potential energy. Thus a paint can being carried up a ladder will lead to increase in potential energy as height will keep on increasing.


lora16 [44]4 years ago
3 0
It is D, a paint can carried up a ladder.
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A periodic wave travels from one medium to another. Which pair of variables are likely to change in the process? A. velocity and
Lesechka [4]

Answer:

A. velocity and wavelength

Explanation:

When a wave travels from one medium to another it undergoes refraction which results to the change in direction.

Refraction of a wave is one of the property of waves that occurs when a wave changes direction when it passes from one medium to another. This occurs as a result of bending of the wave which occurs since the mediums involved are of different density and refractive index.

Apart from the change in direction, refraction is accompanied by the change in wavelength of a wave and thus a change in speed.

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3 years ago
If your car tachometer says your engine is moving at 1200 RPM, then what is it's angular velocity in Rad/sec?
Ostrovityanka [42]

Answer:

125.66 R/s

Explanation:

First    1200  r / min = 20 r/sec

20 r/s  *  2pi Radians / r = 40 pi Radians / sec = 125.66 R/s

3 0
2 years ago
A small segment of wire contains 10 nC of charge. The segment is shrunk to one-third of its original length. A proton is very fa
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To solve this problem we will apply the concepts related to the electric field, linear charge density and electrostatic force.

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E = \frac{\lambda}{2\pi \epsilon_0 r}

Here,

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r = Distance

The linear charge density can be written as,

Linear charge density is given as

\lambda = \frac{q}{L}

Replacing,

E = \frac{\frac{q}{L}}{2\pi \epsilon_0 r}

E = \frac{q}{2\pi \epsilon_0 rL}

The initial and final electric Force can be written as function of the charge and the electric field as

F_i = E_i q

F_f = E_f q

If we replace the value for the electric field we have,

F_i = (\frac{q}{2\pi \epsilon_0 rL})q = (\frac{q^2}{2\pi \epsilon_0 rL})

Length is one third at the end, then

F_f = (\frac{q}{2\pi \epsilon_0 r(L/3)})q = (\frac{3q^2}{2\pi \epsilon_0 rL})

The ratio of the force is

\frac{F_f}{F_i} = \frac{(\frac{3q^2}{2\pi \epsilon_0 rL})}{(\frac{q^2}{2\pi \epsilon_0 rL})}

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Therefore the required ratio is 3

7 0
3 years ago
The radioactive element polonium decays according to the law given below where Q0 is the initial amount and the time t is measur
kogti [31]

Answer:

1280 mg

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140 is the half-life of the polonium, in days (it is the time it takes for the initial element to halve its amount)

IN this problem, we know that:

After t = 560 days, the amount of polonium left is Q(t)=80 mg. Therefore, we can re-arrange the equation, substituting t = 560 d, and solve for Q_0 to find the initial amount of polonium:

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5 0
4 years ago
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cluponka [151]

Answer:

To make an inference what needs to be in the text in the order for you is explained below in complete details.

Explanation:

Making an inference requires using what you recognize to guess what you don't understand or understanding between the series. Scholars who make inferences use the evidence in the text along with their own practices to encourage them to figure out what is not straight said, making the text special and remarkable.

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