Is it true muscle mass affects someones flexibility

. A proton, which moves perpendicular to a magnetic field of 1.2 T in a circular path of radius 0.080 m, has what speed? (qp = 1

almond37 [142]

Answer:

$9.198\times 10^6 m/s$

Explanation:

We are given that

Magnetic field, B=1.2 T

Radius of circular path, r=0.080 m

$q_p=1.6\times 10^{-19} C$

$m_p=1.67\times 10^{-27} kg$

$\theta=90^{\circ}$

We have to find the speed of proton.

We know that

Magnetic force, F= $qvBsin\theta$

According to question

Magnetic force=Centripetal force

$q_pvBsin90^{\circ}=\frac{m_pv^2}{r}$

$1.6\times 10^{-19}\times 1.2=\frac{1.67\times 10^{-27}v}{0.08}$

$v=\frac{1.6\times 10^{-19}\times 1.2\times 0.08}{1.67\times 10^{-27}}$

$v=9.198\times 10^6 m/s$

5 0

4 years ago

The electricity went out at José's home, and he lit some candles until the lights came back on. The candle wax near the wick bec

Verdich [7]

It’s A. Amorphous solid

5 0

4 years ago

Read 2 more answers

Mario uses a hot plate to heat a beaker of 150mL of water. He used a

riadik2000 [5.3K]

Answer:

the point of the BOILING point DOES NOT CHANGE

T = 100ºC

Explanation:

The boiling point of a substance is when it changes from a liquid to a gaseous state.

This point depends on the forces that join the molecules of the liquid, if we take the macroscopic variables of thermodynamics: Temperature, pressure depends on the two in a phase diagram, but nowhere is it dependent on the amount of matter.

Therefore the point of the BOILING point DOES NOT CHANGE

T = 100ºC

8 0

3 years ago

A crate is given a quick push at the bottom of a loading ramp. The box slides up the ramp, and then slides back down. If there i

tamaranim1 [39]

Answer:

The slide back down takes longer than the slide up.

Explanation:

In this is problem, the loss of energy is a key factor.

When the box is pushed up the ramp, it gains a specific speed, and an associated kinetic energy<em>. </em>As it slides up, it losses kinetic energy due to the gravitational and frictional forces, and it is transformed to gravitational potential energy (or potential energy). When it reaches its highest point, the speed becomes cero and all its kinetic energy is converted to potential energy.

However, since there is a frictional force, some amount of energy is loss, so the potential energy is lesser than the initial kinetic energy.

The same occurs when the box slides back down: its potential energy is converted into kinetic energy, but some energy is loss due to the frictional force. This means that the final kinetic energy is smaller than the initial, which implies that its final velocity is smaller than the initial velocity.

Using the acceleration definition:

$a=\frac{v_f-v_o}{t}$

We solve for the time (t) and get:

$t=\frac{v_f-v_o}{a}$

We have to use this equation two times, one for each movement (slide up and slide down).

The gravitational force points down with the same magnitude in both, but the frictional force goes down when the box is sliding up and it goes up when the box slides down. So the magnitude of the acceleration when it goes up is smaller than the other one.

If we analyze both situations:

A) When it goes up:

$t_{up}=-\frac{v_o}{a_1}$