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3 years ago

An electromagnet is a temporary magnet due to which of the following?

Physics

2 answers:

mixer [17]3 years ago

7 0

Answer:

The magnet is only present when a current is present.

Explanation:

As we know that in electromagnet there is a coil of certain resistance which is connected to a energy source which will provide constant potential difference to the coil

Due to constant potential difference the coil will have a current flow in it due to which there exist a magnetic field along the axis of the coil

this magnetic field is only possible when current is flowing in the coil

So it is given as

$B = \frac{\mu_0 N i}{L}$

here we know

N = number of turns

L = length of solenoid

i = current in it

So correct answer is

The magnet is only present when a current is present.

chubhunter [2.5K]3 years ago

5 0

I think the correct answer from the choices listed above is the first option. An electromagnet is a temporary magnet because the magnet is only present when a current is present. The magnetic field disappears when the current is turned off. Hope this answers the question. Have a nice day.

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Prove that young modulus of elasticity and pressure have the same dimensions

ivann1987 [24]

Answer:

The dimensions of Young's Modulus, as well as material stress, are the same as pressure because stress is like pressure in a solid, except with some key differences that warrant the use of different terminology.

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3 years ago

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MrMuchimi

Your answer is french

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3 years ago

The time period T of a simple pendulum is given by the relation

Vanyuwa [196]

Answer:

$T^2 \propto L$

Explanation:

The period of a simple pendulum is given by:

$T=2\pi \sqrt{\frac{L}{g}}$

where

L is the length of the pendulum

g is the acceleration of gravity

From this equation we can write

$T\propto \sqrt{L}\\T\propto \frac{1}{\sqrt{g}}$

Taking the square of this equation, we get:

$T^2 = (2\pi)^2 \frac{L}{g}$

So we see that $T^2$ is proportional to L and inversely proportional to g. So, we can write:

$T^2 \propto L\\T^2 \propto \frac{1}{g}$

So the only correct option is

$T^2 \propto L$

5 0

4 years ago

Read 2 more answers

You put a 3 kg block in the box, so the total mass is now 9 kg, and you launch this heavier box with an initial speed of 5 m/s.

OlgaM077 [116]

Answer:

Δt=0.85 seconds

Explanation:

In this chase the speed does not change as the mass change.So we can use the follow equation to find the required time

Δt=Δv/gμ

To stop the final speed will be zero therefore the change in speed will be

Δv= vf-vi

Δv=0-5 m/s

Δv= -5 m/s

Now we plug our values for Δv,g and μ to find time

Δt=Δv/gμ

Δt=(-5m/s) ÷(9.8m/s² × 0.6)

Δt=0.85 seconds

8 0

3 years ago

A question for the physicists out there:

Tomtit [17]

I don't think that's exactly what this website is here for. / / / The average current = 30 C / 120 sec = 250 mA. / / / 1 volt = 1 joule/coulomb ... 30 C x 1.5 x 10^6 J/C = 4.5 x 10^7 joules per stroke. / / / Apoligies for the formatting. Some websites recognize a CR-LF from a mobile device, and others don't.

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4 years ago