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ira [324]
3 years ago
10

A 5000-km long cable consists of seven copper wires, each of diameter 0.85 mm, bundled together and surrounded by an insulating

sheath. Calculate the resistance of the cable. Use 3x10^-6 cm.Ω for the resistivity of the copper.
Physics
1 answer:
sladkih [1.3K]3 years ago
4 0

Answer:

The resistance of the cable is 37762.91 ohms.

Explanation:

let L be the length of the cable, A be the cross-sectional area of the cable and   r be the resistivity of the copper.

then, the resistance of the cable is given by:

R = r×L/A

  = (3×10^-8)×(5000×10^3)/(7×π((0.85×10^-3)/2)^2)

  = 37762.91 ohms

Therefore, the resistance of the cable is 37762.91 ohms.

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In a chemical reaction, molecules of hydrogen gas (H2) react with molecules of oxygen gas (O2) in a sealed reaction chamber to p
11Alexandr11 [23.1K]

Answer:

Option (B) is correct.

Explanation:

Given that the molecules of hydrogen gas (H_2) react with molecules of oxygen gas (O_2) in a sealed reaction chamber to produce water (H_2O).

The governing equation for the reaction is

2H_2 +O_2 \rightarrow 2H_2O

From the given, the only fact that can be observed that 2 moles of H_2 and 1 mole of O_2 reacts to produce 2 moles of H_2O.

As the mass of 1 mole of H_2 = 2 grams ... (i)

The mass of 1 mole of O_2 = 32 grams ...(ii)

The mass of 1 mole of H_2O = 18 grams (iii)

Now, the mass of the reactant = Mass of 2 moles of H_2 + mass 1 mole of  O_2

= 2 \times 2 + 32  [ using equations (i) and (ii)]

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=36 grams

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8 0
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