You put a 3 kg block in the box, so the total mass is now 9 kg, and you launch this heavier box with an initial speed of 5 m/s.
1 answer:
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<u>Explanation:</u>
Velocity of B₁ = 4.3m/s
Velocity of B₂ = -4.3m/s
For perfectly elastic collision:, momentum is conserved
where,
m₁ = mass of Ball 1
m₂ = mass of Ball 2
v₁ = initial velocity of Ball 1
v₂ = initial velocity of ball 2
v'₁ = final velocity of ball 1
v'₂ = final velocity of ball 2
The final velocity of the balls after head on elastic collision would be
Substituting the velocities in the equation
If the masses of the ball is known then substitute the value in the above equation to get the final velocity of the ball.
Answer:
The speed of the big fish after swallowing the small fish is 0.38 m/s.
Explanation:
Consider west to east direction as positive and the opposite direction as negative.
Given:
Mass of big fish (m₁) = 12.0 kg
Initial velocity of big fish (u₁) = 75 cm/s = 0.75 m/s
Mass of small fish (m₂) = 1 kg
Initial velocity of small fish (u₂) = -4 m/s (Direction is opposite to u₁)
After swallowing the small fish, both the fishes move together with same velocity. Let the velocity be 'v'.
So, as there are no effects of drag or any other forces, the given scenario can be considered as a case of inelastic collision where the objects move together with same velocity after collision.
The momentum is conserved in inelastic collision. Therefore,
Initial momentum of the fishes = Final momentum of the fishes
Now, plug in the given values and solve for 'v'. This gives,
Therefore, the speed of the big fish after swallowing the small fish is 0.38 m/s