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user100 [1]
3 years ago
14

You put a 3 kg block in the box, so the total mass is now 9 kg, and you launch this heavier box with an initial speed of 5 m/s.

How long does it take to stop? Δt = s
Physics
1 answer:
OlgaM077 [116]3 years ago
8 0

Answer:

Δt=0.85 seconds

Explanation:

In this chase the speed does not change as the mass change.So we can use the follow equation to find the required time

Δt=Δv/gμ

To stop the final speed will be zero therefore the change in speed will be

Δv= vf-vi

Δv=0-5 m/s

Δv= -5 m/s

Now we plug our values for  Δv,g and μ to find time

Δt=Δv/gμ

Δt=(-5m/s) ÷(9.8m/s² × 0.6)

Δt=0.85 seconds

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Explain why we say that energy from the washing machine is wasted' as thermal energy?
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2 years ago
A 2.00 kg object is attached to a spring and placed on frictionless, horizontal surface. Ahorizontal force of 18.0 N is required
velikii [3]

Answer:

6 rad/s

Explanation:

In a spring the angular frequency is calculated as follows:

\omega=\sqrt{\frac{k}{m} }

where \omega is the angular frequency, m is the mass of the object in this case m=2kg, and k is the constant of the spring.

To calculate the angular frequency, first we need to find the constant k which is calculated as follows:

k=\frac{F}{x}

Where F is the force: F=18N, and x is the distance from the equilibrium position: x=0.25m.

Thus the spring constant:

k=\frac{18N}{0.25m}

k=72N/m

And now we do have everything necessary to calculate the angular frequency:

\omega=\sqrt{\frac{k}{m} }=\sqrt{\frac{72N/m}{2kg} }=\sqrt{36}

\omega=6rad/s

the angular frequency of the oscillation is 6 rad/s

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Diagnostic ultrasound of frequency 4.50 MHz is used to examine tumors in soft tissue. (a) What is the wavelength in air of such
mafiozo [28]

(a) 7.62 \times 10^{-5} m is the wavelength in air of such a sound wave.

(b) 3.33 \times 10^{-4}\ m is the wavelength of this wave in tissue.

<u>Explanation:</u>

Frequency and wavelength can be related by the equation,

              Velocity = Wavelength x Frequency

              v=\lambda \times f

where,

v - velocity of light for all EM (electromagnetic) waves in vacuum

Given:

f - 4.50 MHz = 4.50 \times 10^{6} \mathrm{Hz}

a) To find the wavelength in air

We know,

Speed of sound in air = 343 m/s

Apply given frequency and speed of sound in air, we get

        \lambda=\frac{v}{f}=\frac{343}{4.5 \times 10^{6}}=76.2 \times 10^{-6}=7.62 \times 10^{-5}\ \mathrm{m}

b) If the speed of sound in tissue is 1500 m/s, find the wavelength of this wave in tissue

Speed of sound in tissue, v = 1500 m/s

        \lambda=\frac{v}{f}=\frac{1500}{4.5 \times 10^{6}}=333.33 \times 10^{-6}=3.33 \times 10^{-4} \mathrm{m}

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