What is the median of the data (180,175,163,186,153,194,198,183,187,174,177,196,162,185,174,195,164,152,144,138,125,110)
allsm [11]
Put them in order from smallest to largest
110, 125, 138 , 144, 152,153,162, 163,164, 174, 174, 175, 177,180,183,185, 186,187, 194,195, 196,198
median = (174 + 175 )/2 = 174.5
answer
174.5
Answer:
60
Step-by-step explanation:
5 plus 4 is nine.
I based everything on how much times more it was at first, and did that times 9 for every name.
I added up how much more boxes they got in total and got 60.
Answer:
Part 1) m∠EFG=94°
Part 2) m∠GFH=86°
Step-by-step explanation:
we know that
m∠EFG+m∠GFH=180° -----> by linear pair (given problem)
we have
m∠EFG=3n+22
m∠GFH=2n+38
substitute the values
(3n+22)°+(2n+38)°=180°
Solve for n
(5n+60)=180
5n=180-60
5n=120
n=24
<em>Find the measure of angle EFG</em>
m∠EFG=3n+22
substitute the value of n
m∠EFG=3(24)+22=94°
<em>Find the measure of angle GFH</em>
m∠GFH=2n+38
substitute the value of n
m∠GFH=2(24)+38=86°
9514 1404 393
Answer:
107°
Step-by-step explanation:
Opposite angles of an inscribed quadrilateral are supplementary.
X = 180° -Q
X = 180° -73° = 107°
Answer:
No, none of the number need to be 48 for the mean to be 48. To get a mean, you add up all the number and divide it by the amount of numbers.
Example:
the mean of 10, 79, 42, 88, 19, and 50 is 48, but the actual number 48 was not part of the set.
10 + 79 + 42 + 88 + 19 + 50 = 288
288 ÷ 6 = 48