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nordsb [41]
3 years ago
11

Need help with 7 and 8

Mathematics
1 answer:
Lostsunrise [7]3 years ago
3 0

Answer:

Step-by-step explanation

7. Find the value of Y

3X+ (8Y-102)+(2Y+6)=360

3X+(8Y+2Y)-102+6=360

3X+10Y-96=360

3X+10Y=456

10Y=456-3X

Y=1/10(456-3X)

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\mathrm{Add\:}\frac{1}{4}\mathrm{\:to\:both\:sides}

\frac{2}{3}\left(cx+\frac{1}{2}\right)-\frac{1}{4}+\frac{1}{4}=\frac{5}{2}+\frac{1}{4}

\frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11}{4}

\mathrm{Multiply\:both\:sides\:by\:}3

3\cdot \frac{2}{3}\left(cx+\frac{1}{2}\right)=\frac{11\cdot \:3}{4}

2cx+1=\frac{33}{4}

\mathrm{Subtract\:}1\mathrm{\:from\:both\:sides}

2cx+1-1=\frac{33}{4}-1

2cx=\frac{29}{4}

\mathrm{Divide\:both\:sides\:by\:}2c

x=\frac{29}{8c}

<h3>Therefore, correct option is C. option.</h3><h3>C. x=29/8c</h3>
8 0
3 years ago
Describe the end behavior of the graph of each polynomial fiction using limits .explain your reasoning using the leading term te
masha68 [24]

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What is the length of the line segment with endpoints (7,-1) and (-3,5)?
Galina-37 [17]

Formula to find the length of two endpoints: \sqrt{(x^2-x^1)^2+(y^2-y^1)^2}

Now, solve with the given endpoints.

\sqrt{(x^2-x^1)^2+(y^2-y^1)^2} \\\sqrt{(-3-7)^2+(5-(-1))^2} \\\sqrt{(-10)^2 + (6)^2} \\ \sqrt{100+36}\\\sqrt{136}

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Now, simplify using what we know about radicals.

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8 0
3 years ago
Solve for slope = 9/4, y-intercept = -4
allsm [11]

Answer:

The equation of the line  with  slope and  y-intercept is y=\frac{9}{4}x-4

Step-by-step explanation:

Given that the slope is \frac{9}{4} and y-intercept=-4

That is m=\frac{9}{4} and c=-4

The slope intercept form is y=mx+c where m is slope and c is y-intercept

Now substitute m=\frac{9}{4} and c=-4 in the above equation we get

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7 0
3 years ago
Triangle ABC is shown below:
NeX [460]

Answer:

(-1, -4)

Step-by-step explanation:

In the graph:

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Since coordinates are in (x, y) the coordinates are (-1, -4)

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

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