Pretend these are coordinates that you can use to find the slope of the line.
(10, 40) and (15, 60). Fit these into the slope formula to find the slope of the line you are looking for:

and the slope is 4. Now use one of the points and the slope of 4 to solve for b, the y-intercept:
40 = 4(10) + b so b = 0. The equation of the line then is y = 4x + 0 or just
y = 4x
Answer:
answer below
Step-by-step explanation:
ABCDE go through dilation over center (6 , -2) with factor of 1/2 to FGHIJ
AB // FG slope: -2 , √20:√5 = 2: 1
BC // GH // X axis 8:4 = 2:1
CD // HI, slope= 1 , √8:√2 = 2:1
DE // IJ // x axis, 4:2 = 2:1
EA // JF // y axis, 2:1
Answer:
i did the first
Step-by-step explanation:
1st way
Standard form: a(X-h)²+k = ( -2/3X² -16/3X -32/3) +32/3 -17/3 = -2/3(X +4)² +5
y = -2/3*X^2-16/3*X-17/3
X = -4 ±√( 15/2) = -6.7386, or -1.2614
Axis of symmetry: X= -4; Vertex (maximum)=(h,k)=( -4, 5); y-intercept is (0,-5.66666666667)
two real roots: X=-1.2613872124776866 and -6.738612787477313
Length=width+x
l=w+x (x being the amount of feet longer than the width)