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3 years ago

I WILL AWARD BRAINLIEST!! PLEASE HELP!!!

Mathematics

1 answer:

lana66690 [7]3 years ago

6 0

$speed = \frac{distance}{time}$

from the question,

the total speed for the pedestrian is

40km and the total time is 10hr

substitute them in the formula, we get

$speed = \frac{40}{10}$

speed = 4km/hr

B. 10hrs - 6hrs = 4hours

C. BC is deacceleration = -dv/dt

CD is constant acceleration = dt = 0

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andrezito [222]

Answer:

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Step-by-step explanation:

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3 years ago

A decorative window is made up of a rectangle with semicircles at either end. The ratio of AD to AB is 3:2 and AB is 30 inches.

scZoUnD [109]

Answer: The required ratio will be

$84:1034$

Step-by-step explanation:

Since we have given that

Ratio of AD to AB is 3:2

Length of AB = 30 inches

So, it becomes

$2x=30\\\\x=\frac{30}{2}=15\ inches$

So, Length of AD becomes

$3x=3\times 15=45\ inches$

Now, at either end , there is a semicircle.

Radius of semicircle along AB is given by

$\frac{30}{2}=15\ inches$

So, Area of semicircle along AB and CD is given by

$2\times \frac{\pi r^2}{2}\\\\=\frac{22}{7}\times 15\times 15\\\\=\frac{4950}{7}\ in^2$

Radius of semicircle along AD is given by

$\frac{45}{2}=22.5\ inches$

Area of semicircle along AD and BC is given by

$2\times \frac{1}{2}\pi r^2\\\\=\frac{22}{7}\times \frac{45}{2}\times \frac{45}{2}\\\\=\frac{445500}{28}\ in^2$

And the combined area of the semicircles is given by

$\frac{4950}{7}+\frac{445500}{28}\\\\=\frac{465300}{28}\ in^2$

Area of rectangle is given by

$Length\times width\\\\=AD\times AB\\\\=45\times 30\\\\=1350\ in^2$

Hence, Ratio of the area of the rectangle to the combined area of the semicircles is given by

$1350:\frac{465300}{28}\\\\=1350\times 28:465300\\\\=37800:465300\\\\=84:1034$

Hence, the required ratio will be

$84:1034$

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3 years ago

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klemol [59]

Idk tbh man I think sumbody else will answer

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3 years ago

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mrs_skeptik [129]

Step-by-step explanation:

5x=4x+12(corresponding angle)

5x-4x=12

x=12

if it is correct answer then please follow me

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3 years ago

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jek_recluse [69]

Answer
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