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3 years ago

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PLS HELP. Write an equation that represents the clues given. Clue #1: The sum of six times the first number and four times the s

econd number is equal to 550. Clue #2: The sum of half the first number and four times the second number is equal to 1000

1 answer:

kkurt [141]3 years ago

4 0

Answer:

Clue#1: 6x+4y=550

Clue #2: 1/2x+4y=1000

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

The first number will be x, and the second number y:

<em>The sum of six times the first number and four times the second number is equal to 550 </em>

Six times the first number means that the first number must be multiplied by 6.(6x); the same for four times the second number (4x).

6x+4y=550

<em>The sum of half the first number and four times the second number is equal to 1000 </em>

Half the first number means the first number (x) divided by 2,or multiplied by 1/2.

1/2x+4y=1000

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Answer: 60, but I got other answers to but 60 was my first.

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Step-by-step explanation:

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3 years ago

Suppose f is a function with exponential growth and f(0)=1. Explain why f can be represented by a formula of the form

galben [10]

We are supposed to explain why the given function can be expressed in form $f(x)=b^{x}$ , when $f(0)=1$ .

Since the given function is an exponential function we can express it as $f(x)=a(b)^{x}$ .

Now let us substitute x=0 in the given function,

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Let us substitute x=0 in our function.

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Upon substituting a=1 in our function we will get,

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3 years ago

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A tank contains 30 lb of salt dissolved in 300 gallons of water. a brine solution is pumped into the tank at a rate of 3 gal/min

sesenic [268]

$A'(t)=(\text{flow rate in})(\text{inflow concentration})-(\text{flow rate out})(\text{outflow concentration})$
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We're given that $A(0)=30$ . Multiply both sides by the integrating factor $e^{t/100}$ , then

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
$\left(e^{t/100}A(t)\right)'=6e^{t/100}+3e^{t/100}\sin\dfrac t4$
$e^{t/100}A(t)=600e^{t/100}-\dfrac{150}{313}e^{t/100}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+C$
$A(t)=600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+Ce^{-t/100}$

Given that $A(0)=30$ , we have

$30=600-\dfrac{150}{313}\cdot25+C\implies C=-\dfrac{174660}{313}\approx-558.02$

so the amount of salt in the tank at time $t$ is

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3 years ago

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julsineya [31]

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3 years ago

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Lorico [155]

Answer:

Let's simplify step-by-step.

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Combine Like Terms:

= 4a+5a^2 + −3a^2+ −6a

= (5a2+ −3a^2) + (4a + −6a)

= 2a2 + −2a

Final Answer:

= 2a^2−2a!

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