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Oliga [24]
3 years ago
7

PLS HELP. Write an equation that represents the clues given. Clue #1: The sum of six times the first number and four times the s

econd number is equal to 550. Clue #2: The sum of half the first number and four times the second number is equal to 1000
Mathematics
1 answer:
kkurt [141]3 years ago
4 0

Answer:

Clue#1:  6x+4y=550

Clue #2:  1/2x+4y=1000

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

The first number will be x, and the second number y:

<em>The sum of six times the first number and four times the second number is equal to 550 </em>

Six times the first number means that the first number must be multiplied by 6.(6x); the same for four times the second number (4x).

6x+4y=550

<em>The sum of half the first number and four times the second number is equal to 1000 </em>

Half the first number means the first number (x) divided by 2,or multiplied by 1/2.  

1/2x+4y=1000

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3 years ago
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Write the numbers in order from least to greatest. 8/10, -.82, 2.5, -9.5
Art [367]

Answer: -9.5, -.82, 8/10, 2.5

Step-by-step explanation:

-9.5 is the least because the bigger the negative number is the smaller it's value is (opposite of positive numbers)

-.82 same thing

8/10 or .8

2.5 same thing as 2.50 so what is greater $2.50 or $0.80 exactly 2.50 is greater so it's the greatest

6 0
3 years ago
Suppose that X has an exponential distribution with mean equal to 10. Determine the following: a. P(X &gt; 10) b. P(X &gt; 20) c
GrogVix [38]

Answer:

(a) The value of P (X > 10) is 0.3679.

(b) The value of P (X > 20) is 0.1353.

(c) The value of P (X < 30) is 0.9502.

(d) The value of x is 30.

Step-by-step explanation:

The probability density function of an exponential distribution is:

f(x)=\lambda e^{-\lambda x};\ x>0, \lambda>0

The value of E (X) is 10.

The parameter λ is:

\lambda=\frac{1}{E(X)}=\frac{1}{10}=0.10

(a)

Compute the value of P (X > 10) as follows:

P(X>10)=\int\limits^{\infty}_{10} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{10} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{10}\\=|e^{-0.10 x} |^{\infty}_{10}\\=e^{-0.10\times10}\\=0.3679

Thus, the value of P (X > 10) is 0.3679.

(b)

Compute the value of P (X > 20) as follows:

P(X>20)=\int\limits^{\infty}_{20} {0.10 e^{-0.10 x}} \, dx \\=0.10\int\limits^{\infty}_{20} { e^{-0.10 x}} \, dx\\=0.10|\frac{e^{-0.10 x}}{-0.10} |^{\infty}_{20}\\=|e^{-0.10 x} |^{\infty}_{20}\\=e^{-0.10\times20}\\=0.1353

Thus, the value of P (X > 20) is 0.1353.

(c)

Compute the value of P (X < 30) as follows:

P(X

Thus, the value of P (X < 30) is 0.9502.

(d)

It is given that, P (X < x) = 0.95.

Compute the value of <em>x</em> as follows:

P(X

Take natural log on both sides.

ln(e^{-0.10x})=ln(0.05)\\-0.10x=-2.996\\x=\frac{2.996}{0.10}\\ =29.96\\\approx30

Thus, the value of x is 30.

7 0
3 years ago
Use the method of completing the square to transform the quadratic equation into the equation form (x + p)2 = q. 3 + x - 3x2 = 9
Triss [41]
To <span>transform the quadratic equation into the equation form (x + p)2 = q we shall proceed as follows:
3+x-3x^2=9
putting like terms together we have:
-3x^2+x=6
dividing through by -3 we get:
x^2-x/3=-2
but
c=(b/2a)^2
c=(-1/6)^2=1/36
thus the expression will be:
x^2-x/3+1/36=-2+1/36
1/36(6x-1)</span>²=-71/36

the answer is:
1/36(6x-1)²=-71/36
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weqwewe [10]

Answer: third dot

Step-by-step explanation:

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