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Oliga [24]
3 years ago
7

PLS HELP. Write an equation that represents the clues given. Clue #1: The sum of six times the first number and four times the s

econd number is equal to 550. Clue #2: The sum of half the first number and four times the second number is equal to 1000
Mathematics
1 answer:
kkurt [141]3 years ago
4 0

Answer:

Clue#1:  6x+4y=550

Clue #2:  1/2x+4y=1000

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

The first number will be x, and the second number y:

<em>The sum of six times the first number and four times the second number is equal to 550 </em>

Six times the first number means that the first number must be multiplied by 6.(6x); the same for four times the second number (4x).

6x+4y=550

<em>The sum of half the first number and four times the second number is equal to 1000 </em>

Half the first number means the first number (x) divided by 2,or multiplied by 1/2.  

1/2x+4y=1000

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Yuri [45]

\implies {\blue {\boxed {\boxed {\purple {\sf { \:  A. \:- 8 {v}^{4}  + 3 {v}^{3}  + v + 5}}}}}}

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

(4 + 6v + 3 {v}^{3} ) - (5v + 8 {v}^{4}  - 1)

➼\: 4 + 6v + 3 {v}^{3}  - 5v  -  8 {v}^{4}  + 1

Combining like terms, we have

➼\: - 8 {v}^{4}  + 3 {v}^{3}  + 6v - 5v + 4 + 1

➼\:  - 8 {v}^{4}  + 3 {v}^{3}  + v + 5

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7 0
3 years ago
The length of the hypotenuse of a right triangle is 24. If the length of one leg is 8, what is approximate length of the other l
Verdich [7]

Something that a right triangle is characterised by is the fact that we may use Pythagoras' theorem to find the length of any one of its sides, given that we know the length of the other two sides. Here, we know the length of the hypotenuse and one other side, therefor we can easily use the theorem to solve for the remaining side.

Now, Pythagoras' Theorem is defined as follows:

c^2 = a^2 + b^2, where c is the length of the hypotenuse and a and b are the lengths of the other two sides.

Given that we know that c = 24 and a = 8, we can find b by substituting c and a into the formula we defined above:

c^2 = a^2 + b^2

24^2 = 8^2 + b^2 (Substitute c = 24 and a = 8)

b^2 = 24^2 - 8^2 (Subtract 8^2 from both sides)

b = √(24^2 - 8^2) (Take the square root of both sides)

b = √512 (Evaluate 24^2 - 8^2)

b = 16√2 (Simplify √512)

= 22.627 (to three decimal places)

I wasn't sure about whether by 'approximate length' you meant for the length to be rounded to a certain number of decimal places or whether you were meant to do more of an estimate based on your knowledge of surds and powers. If you need any more clarification however don't hesitate to comment below.

4 0
3 years ago
Quick algebra 1 question for 50 points!
snow_tiger [21]

Answer:

Yes.

Step-by-step explanation:

Yes, the given line can be used to make reasonable predictions of the number of cheese pizzas that will be sold, since the scatter points clearly show a trend.

As time goes on, the number of pizzas sold is getting bigger, and the trend is what created the line.

The data was taken over 8 consecutive weeks, so we can assume that it can be used in our prediction.

Since the trend has been pretty consistent over periods of time, we can expect it to continue in the upcoming weeks.

3 0
2 years ago
Jon recently drove to visit his parents who live 280 miles away. On his way there his average speed was 9 miles per hour faster
Luba_88 [7]

Answer:

11 mph and 20 mph

Step-by-step explanation:

Represent his average speed going by r1 and his average speed returning by r2.  We know that r1 = r2 + 9.

Recall that distance = rate times time, so time = distance / rate.

Time spent going was (280 mi) / r1, or (280 mi) / (r2 + 9 mph).

Time spend returning was (280 mi) / r2.

The total time was 14 hrs, so (280 mi) / (r2 + 9 mph) + (280 mi) / r2 = 14 hrs

Note that there is only one variable here:  r2.  Find r2, and then from r2, find r1:

Dividing all 3 terms by 14 hrs yields:

  20            20

---------- + ----------- = 1

r2 + 9         r2

The LCD here is r2(r2 + 9).  Thus, we have:

      20r2                    (r2 +  9)(r2)

------------------- = 1 or  ------------------

 (r2 +  9)(r2)               (r2 +  9)(r2)

Then 20(r2) = (r2)^2 + 9(r2).  This is reducible by dividing all terms by r2:

20 = r2 + 9, or 11 = r2.  Then r1 = 11 + 9, or 20.

The two rates were 11 mph and 20 mph.

8 0
3 years ago
20 POINTS!!!!!!!
zavuch27 [327]
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8 0
3 years ago
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