The data set below represents the ages of 11 kids in an after-school program. 10, 11, 8, 7, 6, 10, 7, 10, 9, 9, 12 Which box plo
Andreas93 [3]
Answer:
This is the answer because you need to find mean median mode range, first quertile, third quartile
Whisker plot below
Step-by-step explanation:
Mean (Average) 9
Median 9
Range 6
Mode 10, appeared 3 times
Geometric Mean 8.8206311297046
Largest 12
Smallest 6
Sum 99
Count 11
■ 1st quartile (lower quartile) = 7.5
■ 2st quartile (median) = 9
■ 3st quartile (upper quartile) = 10
Answer:
domain is basically x and range is y, so -2,5 -2 is domain and 5 is range
Step-by-step explanation:
Answer:
4 then 6 then 8
Step-by-step explanation:
2×2=4
2×3=6
2×4=8
<h3>
Answer: 15 years old</h3>
=============================================
Explanation:
m = Maggie's age (some positive whole number)
4m = four times her age
4m-7 = seven years younger than 4m = brother's age
Add up her age (m) and her brother's age (4m-7) to get a sum of 68.
m+(4m-7) = 68
5m-7 = 68
5m = 68+7
5m = 75
m = 75/5
m = 15
Maggie is currently 15 years old.
Her brother is currently 4m-7 = 4*15-7 = 60-7 = 53 years old.
Their current year ages add to: 15+53 = 68 which confirms the answer.
The markup percentage is 45.14%
Step-by-step explanation:
The given is:
- The selling price of a box of crackers is $1.75
- You mark the crackers up to $2.54
We need to find the markup percentage
The markup percentage =
× 100%
∵ The selling price of a box of crackers is $1.75
∴ Old = 1.75
∵ You mark the crackers up to $2.54
∴ New = 2.54
- Substitute these values in the rule above
∵ The markup percentage =
× 100%
∴ The markup percentage =
× 100%
∴ The markup percentage = 0.4514 × 100%
∴ The markup percentage = 45.14%
The markup percentage is 45.14%
Learn more:
You can learn more about percentage in brainly.com/question/1834017
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