1. AB is tangent to circle O at B. The diagram is not drawn to scale. . . circle O. . If AB = 9 and AO = 21.6, what is the lengt
h of the radius (r)? Round the answer to the nearest tenth. A. 19.6. B.15.3*. C.23.4. D.12.6. 2. JK, KL, and LJ are all tangent to circle O. The diagram is not drawn to scale. . . triangle JLK with an inside circle O. . If JA = 12, AL = 15, and CK = 5, what is the perimeter of ΔJKL? (1 point). 34. 64 *. 32. 54. 3. WZ and XR are diameters of circle C. The diagram is not drawn to scale. . . . . What is the measure of ____ A. 355º. B.5º. C. 292º. D.243º.
2 answers:
1) The correct answer is A) 19.6
See the first picture attached.
A line tangent with a circle (AB) forms a 90° angle with the radius drawn from the tangent point (BO). This means that you can apply the Pythagorean theorem:
BO = √(AO² - AB²)
= √(21.6² - 9²)
= √(466.56 - 81)
= √385.56
= 19.6
2) The correct answer is B) 64
See the second picture attached.
When you have an incircle (a circle inscribed in a triangle), the distances between a vertex and the two nearest tangent points are equal to each other.
This means that:
JA = JB
LA = LC
KC = KB
Therefore the perimeter of ΔJKL will be:
2 × (12 + 15 + 5) = 64
3) The question asks for the measure of arc ZWX
The correct answer is D) 243°
See the third picture attached.
We know that a diameter forms an arc of 180°, because it divides the circle into two equal parts.
Therefore, arc ZRW measures 180°.
In order to find arc ZWX you need to add arc ZRW and arc WX:
ZWX = ZRW + WX
= 180 + 63
= 243°
See the first picture attached.
A line tangent with a circle (AB) forms a 90° angle with the radius drawn from the tangent point (BO). This means that you can apply the Pythagorean theorem:
BO = √(AO² - AB²)
= √(21.6² - 9²)
= √(466.56 - 81)
= √385.56
= 19.6
2) The correct answer is B) 64
See the second picture attached.
When you have an incircle (a circle inscribed in a triangle), the distances between a vertex and the two nearest tangent points are equal to each other.
This means that:
JA = JB
LA = LC
KC = KB
Therefore the perimeter of ΔJKL will be:
2 × (12 + 15 + 5) = 64
3) The question asks for the measure of arc ZWX
The correct answer is D) 243°
See the third picture attached.
We know that a diameter forms an arc of 180°, because it divides the circle into two equal parts.
Therefore, arc ZRW measures 180°.
In order to find arc ZWX you need to add arc ZRW and arc WX:
ZWX = ZRW + WX
= 180 + 63
= 243°
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The approximate equation in slope intercept form is y = 3x + 2.
Solution:
Let us take (0, 2) and (1, 5) on the graph.
Equation of the line in slope-intercept form:
y = mx + b
where m is the slope of the line and b is the y-intercept of the line.
Slope of the line:
m = 3
y-intercept of the line is the value of y when x = 0.
Here the value of y is 2 when x = 0. That is (0, 2) is the point of y-intercept.
Therefore b = 2.
y = 3x + 2
Hence the approximate equation in slope intercept form is y = 3x + 2.