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Veronika [31]
3 years ago
14

1. AB is tangent to circle O at B. The diagram is not drawn to scale. . . circle O. . If AB = 9 and AO = 21.6, what is the lengt

h of the radius (r)? Round the answer to the nearest tenth. A. 19.6. B.15.3*. C.23.4. D.12.6. 2. JK, KL, and LJ are all tangent to circle O. The diagram is not drawn to scale. . . triangle JLK with an inside circle O. . If JA = 12, AL = 15, and CK = 5, what is the perimeter of ΔJKL? (1 point). 34. 64 *. 32. 54. 3. WZ and XR are diameters of circle C. The diagram is not drawn to scale. . . . . What is the measure of ____ A. 355º. B.5º. C. 292º. D.243º.

Mathematics
2 answers:
olganol [36]3 years ago
8 0
1) The correct answer is A) 19.6

See the first picture attached.

A line tangent with a circle (AB) forms a 90° angle with the radius drawn from the tangent point (BO). This means that you can apply the Pythagorean theorem:
BO = √(AO² - AB²)
      = √(21.6² - 9²)
      = √(466.56 - 81)
      = √385.56
      = 19.6

2) The correct answer is B) 64

See the second picture attached.

When you have an incircle (a circle inscribed in a triangle), the distances between a vertex and the two nearest tangent points are equal to each other.

This means that:
JA = JB
LA = LC
KC = KB

Therefore the perimeter of ΔJKL will be: 
2 × (12 + 15 + 5) = 64

3) The question asks for the measure of arc ZWX
The correct answer is D) 243°

See the third picture attached.

We know that a diameter forms an arc of 180°, because it divides the circle into two equal parts.

Therefore, arc ZRW measures 180°.

In order to find arc ZWX you need to add arc ZRW and arc WX:
ZWX = ZRW + WX
         = 180 + 63
         = 243°

ArbitrLikvidat [17]3 years ago
6 0
The answers are :
A) 19.6
B) 64
D) 243°

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Answer:

-1, 2, 6

Step-by-step explanation:

We have to solve the equation as follows: 1/(x-6) + (x/(x-2)) = (4/(x²-8x+12)).

Now, we have, \frac{1}{x-6} +\frac{x}{x-2} = \frac{4}{x^{2}-8x+12 }

⇒\frac{(x-2)+x(x-6)}{(x-2)(x-6)} = \frac{4}{x^{2}-8x+12 }

⇒\frac{x-2+x^{2}-6x }{(x-2)(x-6)} =\frac{4}{(x-2)(x-6)}

⇒\frac{(x-2)(x-6)}{x^{2}-5x-2 }=\frac{(x-2)(x-6)}{4}

⇒(x-2)(x-6)[\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0

⇒ (x-2)(x-6) =0 or, [\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0

If, (x-2)(x-6) =0, then x=2 or x=6

If, [\frac{1}{x^{2} -5x-2} -\frac{1}{4} ]=0, then x^{2} -5x-2=4

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Answer:

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Step-by-step explanation:

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Answer:

The answer is given below

Step-by-step explanation:

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There exist two real numbers such that their sum is less than the difference between them

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n²≥n means that the square of n is greater or equal to n.

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The statement is true.

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