G(x) = 3x - 5
let g(x) = y
y = 3x - 5
y + 5 = 3x
3x = y + 5
x = (y + 5)/3
From y = g(x), x = g⁻¹(y)
<span>x = (y + 5)/3
</span>
g⁻¹(y) = <span>(y + 5)/3</span>
g⁻¹(x) = <span>(x + 5)/3</span>
19.) 14/18, 21/27
20.) 3/21, 2/14
21.) 6
22.)8/9
25.) 36/73
26.) 1/3=.33 2/8=.25 Eric is more successful
Answer:
Step-by-step explanation:
For this case, the first thing we must do is define variables.
We have then:
n: number of cans that each student must bring
We know that:
The teacher will bring 5 cans
There are 20 students in the class
At least 105 cans must be brought, but no more than 205 cans
Therefore the inequation of the problem is given by:
Answer:
105 <u><</u> 20n + 5 <u><</u> 205
the possible numbers n of cans that each student should bring in is:
105 <u><</u> 20n + 5 <u><</u> 205
This is hard I’m not sure
