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3 years ago

5

The sum of two numbers is -5. Which graph represents this situation?

1 answer:

RUDIKE [14]3 years ago

6 0

Answer:

(-5)-x=(-5)

Step-by-step explanation:

-(5)-x=-5()

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Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$

NOTE: sin²θ + cos²θ = 1

$\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{sin^2\theta-cos^2\theta}$

$\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}$

$\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}$

$\dfrac{2sec^2\theta}{tan^2\theta-1}$

Left side = Right side <em>so proof is complete</em>

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Please solve for y! I will make the first answer brainlist!(sorry if I spelled it wrong) :)

Lapatulllka [165]

Answer:

y = -5

Step-by-step explanation:

<em>-</em><em>7</em> = <em>y </em><em>-</em><em>2</em><em> </em>

<em>y </em><em>=</em><em> </em><em>-</em><em>7</em><em> </em><em>+</em><em>2</em>

<em>y </em><em>=</em><em> </em><em>-</em><em> </em><em>5</em><em> </em>

<em>plz </em><em>mark</em><em> my</em><em> answer</em><em> as</em><em> brainlist</em><em>.</em><em>.</em>

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Marizza181 [45]

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