Hello,
if the solution is infinite : the line x-3y=4 ,
so there is one line and not 2
==>x-3y=4 multiplied by 2
2x-6y=8=Q
Q=8
<span>1. line goes through the points (9, 10) and (-3, 2). (a) What is the slope of the line? Show your work
slope = (10 - 2)/(9 + 3)
slope = 8/12
slope = 2/3
</span><span>2. Write the equation of the line in point-slope form.
Show your work
</span>
point-slope form. <span>
y - y1 = m(x - x1)
so equation
y - 2 = 2/3(x + 3)
</span><span>3. Write the equation of the line in slope-intercept form.
Show your work.</span><span>
</span>slope = 2/3, passing thru <span> (-3, 2)
</span><span>
y = mx + b
b = y - mx
b = 2 - (2/3)(-3)
b = 2 + 2
b = 4
equation
y = 2/3(x) + 4
</span>
Answer:
a) 48.408
b) 1.235
Step-by-step explanation:
a)
The average hardness value xbar can be computed as
xbar=sum of values/number of values
xbar=(46.5+46.9+49.4+50.3+49.8+48.8+47+47.7+48.3+49.4+47.8+49)/12
xbar=580.9/12
xbar=48.408 (rounded to 3 decimal places).
The average hardness value is 48.408.
b)
The standard deviation hardness value s can be computed as

x x-xbar (x-xbar)
²
46.5 -1.90833 3.64174
46.9 -1.50833 2.27507
49.4 0.99167 0.98340
50.3 1.89167 3.57840
49.8 1.39167 1.93674
48.8 0.39167 0.15340
47.0 -1.40833 1.98340
47.7 -0.70833 0.50174
48.3 -0.10833 0.01174
49.4 0.99167 0.98340
47.8 -0.60833 0.37007
49.0 0.59167 0.35007
Total 16.7692




s=1.235 (rounded to 3 decimal places)
The standard deviation hardness value is 1.235.