Question

Choose the correct simplification of d to the 7th power times g to the 13th power all over d to the 2nd power times g to the 7th power.
d9g20
1 over d to the 5th power times g to the 6th power
1 over d to the 9th power times g to the 20th power
d5g6

Answer 1

Correct answer would be d to the 5th power over g to the 6th power

Answer 2

Answer:

Option 4

Step-by-step explanation:

Given : d to the 7th power times g to the 13th power all over d to the 2nd power times g to the 7th power.

To find : The correct  simplification

Solution :

d to the 7th power = $d^7$

g to the 13th power = $g^{13}$

d to the 7th power times g to the 13th power =  $d^7\times g^{13}$

d to the 2nd power = $d^2$

g to the 7th power = $g^7$

d to the 2nd power times g to the 7th power =  $d^2\times g^{7}$

According to question,

d to the 7th power times g to the 13th power all over d to the 2nd power times g to the 7th power.

$=\frac{d^7\times g^{13}}{d^2\times g^7}$

$=d^{7-2}\times g^{13-7}$

$=d^{5}\times g^{6}$

Therefore, Option 4 is correct.