3 years ago

X(x + 2) = 83.7 rounded to the nearest hundred

Mathematics

1 answer:

Bogdan [553]3 years ago

6 0

This really has two solutions. The first one being -10.2 and the second one being 8.2.

You might be interested in

Choose the Athat seems to be congruent to the given one.

julia-pushkina [17]

Answer:

a. ∆EGF ≅ ∆EGD

Step-by-step explanation:

Congruent triangles would have the same side lengths and the same measure of angles.

From the figure given:

EG in ∆EGF ≅ EG in ∆EGD

GF in ∆EGF ≅ GD in ∆EGD, also

EF ≅ ED.

The three angles in ∆EFG are also congruent to the three angles in ∆EGD.

Therefore, ∆EGD is congruent to ∆EGF.

∆EGF ≅ ∆EGD

7 0

3 years ago

Find the circumference of the following circle. Use 3.14 for π. Round to the nearest hundredth, if necessary.

dybincka [34]

Answer:

18.84

Step-by-step explanation:

3.14 · 6

18.84

3 0

4 years ago

Read 2 more answers

My question is in the picture please help. First answer gets brainliest

Mandarinka [93]

Round 1 player 1 because 12 is the greatest number

5 0

3 years ago

Help me pleaseee finically algebra please I need help

maxonik [38]

Answer:

$7,367.43

Step-by-step explanation:

6 0

3 years ago

Simplify this step by step<br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B-5jk%7D%7B35j%5E2k%5E2%7D%20" id="TexFormula1" tit

VikaD [51]

$\frac { -5jk }{ 35{ j }^{ 2 }{ k }^{ 2 } } \\ \\ =-\frac { 5 }{ 35 } \cdot \frac { j }{ { j }^{ 2 } } \cdot \frac { k }{ { k }^{ 2 } } \\ \\ =-\frac { 1 }{ 7 } \cdot \frac { 1 }{ j } \cdot \frac { 1 }{ k } \\ \\ =-\frac { 1 }{ 7jk }$

Remember that:

$\frac { j }{ { j }^{ 2 } } =\frac { 1 }{ j } \cdot \frac { j }{ j } =\frac { 1 }{ j } \cdot 1=\frac { 1 }{ j } \\ \\ \frac { k }{ { k }^{ 2 } } =\frac { 1 }{ k } \cdot \frac { k }{ k } =\frac { 1 }{ k } \cdot 1=\frac { 1 }{ k }$

8 0

3 years ago

Read 2 more answers