Question

What is the area of one of the triangular faces? —In.2

Answer 1

Answer:

6 inches squared

Step-by-step explanation:

gimmie brainlist please or ill EAT you wittle bwain UwU

Answer 2

Answer:

6 inches squared

Step-by-step explanation:

The triangle is a right triangle. We can see this because it is attached a rectangle, which has angles of 90 degrees.

Now, notice that the hypotenuse is given as 5 inches and one of the legs is given as 3 inches. We can use the Pythagorean Theorem to find the third side: x = $\sqrt{5^2-3^2} =\sqrt{25-9} =\sqrt{16} =4$

The area of a triangle is A = (1/2) * b * h, where b is the base and h is the height perpendicular to the base. We know the base is 3, so b = 3, and we also see that the height is 4, so h = 4. Plugging these in:

A = (1/2) * b * h = (1/2) * 3 * 4 = 6

Thus, the area of one of the triangular faces is 6 inches squared.

Hope this helps!