Answer:
R=P+C
Step-by-step explanation:
These ones are really simple. To solve these you just need to get a certain value by itself and in this case, it is R. To solve this just add C because it is negative and make sure to add it to both sides and there's your answer.
Given that the roots of the equation x^2-6x+c=0 are 3+8i and 3-8i, the value of c can be obtained as follows;
taking x=3+8i and substituting it in our equation we get:
(3+8i)^2-6(3+8i)+c=0
-55+48i-18-48i+c=0
collecting the like terms we get:
-55-18+48i-48i+c=0
-73+c=0
c=73
the answer is c=73
By rearranging x = 7y - 5 to make y the subject, we get
x + 5 = 7y ( By transposition method )
or, 
<h2>Answer:</h2>
Answer:
Step 2:
Part A
f(x) = a(x-h)^2 +k
Part B
I'm not really sure about this part
Part C
f(x)=-12/25(x-25)^2+32
Step 3:
Part A
y = ax^2 + bx + c
Part B
f(x) = -12/25(x - 25)^2 + 32
Part C
a = -12/25
b = 0
c = 32
Step-by-step explanation:
Hope This Helps!
Sorry For Taking So Long!
<u>Answer:</u>
<h2>(4, 6)</h2>
<u>Explanation:</u>
x = -4 + (12 - (-4))/2
x = -4 + (12+4)/2
x = -4 + 16/2
x = -4 + 8
x = 4
y = 2 + (10 - 2)/2
y = 2 + 8/2
y = 2 + 4
y = 6
the coordinates of the center of the circle: (4, 6)
