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nasty-shy [4]
3 years ago
12

Solve the system of equations:

Mathematics
1 answer:
Ahat [919]3 years ago
8 0

Answer:

Step-by-step explanation:

z = 3

2y + z = 1

2y + 3 = 1        {substituting z =3}

2y = 1 -3

2y = -2

y = - 2/2

y = -1

2x +3y +2z = 13

2x + 3 * (-1) + 2*3 = 13      { {substituting z =3} and y = -1}

2x -3 + 6 =13

2x + 3 = 13

2x  = 13 - 3

2x= 10

x = 10/2

x = 5

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Confidence Interval Mistakes and Misunderstandings—Suppose that 500 randomly selected recent graduates of a university were as
kvv77 [185]

Answer:

The correct 95% confidence interval is (8.4, 8.8).

Step-by-step explanation:

The information provided is:

n=500\\\bar x=8.6\\\sigma=2.2

(a)

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The 95% confidence interval for the average satisfaction score is computed as:

8.6 ± 1.96 (2.2)

This confidence interval is incorrect.

Because the critical value is multiplied directly by the standard deviation.

The correct interval is:

8.6\pm 1.96 (\frac{2.2}{\sqrt{500}})=8.6\pm 0.20=(8.4,\ 8.6)

(b)

The (1 - <em>α</em>)% confidence interval for the parameter implies that there is (1 - <em>α</em>)% confidence or certainty that the true parameter value is contained in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true there is a 95% confidence that the true parameter value is contained in this interval.

The mistake is that the student concluded that the sample mean is contained in between the interval. This is incorrect because the population is predicted to be contained in the interval.

(c)

The (1 - <em>α</em>)% confidence interval for population parameter implies that there is a (1 - <em>α</em>) probability that the true value of the parameter is included in the interval.

The 95% confidence interval for the mean rating, (8.4, 8.8) implies that the true mean satisfaction score is contained between 8.4 and 8.8 with probability 0.95 or 95%.

Thus, the students is not making any misinterpretation.

(d)

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

In this case the sample size is,

<em>n </em>= 500 > 30

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7 0
3 years ago
What is 14/40 reduced
mamaluj [8]

Answer:

7/20

Step-by-step explanation:

3 0
3 years ago
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maks197457 [2]

Answer:

1) S(t) = C(t) × D(t)

2) S(t) = (400 + 30t)(25 + t)

Step-by-step explanation:

The function C(t) = 400 + 30t ........... (1), models the number of classrooms, C. in the town of Sirap, t years from  now.  

The function D(t) = 25 + t ......... (2) models the number of students per classroom, D, t years from now.

Then if S(t) represents the number of students in Sirap's school system t years from now, then, we can write the relation  

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The total cost would be the number of nights multiplied by the cost per night added to the entry fee.

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