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Nookie1986 [14]
3 years ago
8

Roberta has $4.00 in dimes and quarters. She has 5 more dimes than quarters. Write a system of equations that you could use to f

ind how many dimes and quarters she has.
Mathematics
1 answer:
MakcuM [25]3 years ago
8 0

Answer:

\left\{\begin{array}{l}25x+10y=400\\y=x+5\end{array}\right..

Step-by-step explanation:

Let x be the number of quaters and y be the number of dimes Roberta has.

1. Quater is equal to 25 cents, then x quaters is equal to 25x cents. Dime is equal to 10 cents, then y dimes is equal to 10y cents. $4.00=400 cents, then

25x+10y=400.

2. Roberta has 5 more dimes than quarters, then

y=x+5.

3. The system of equations is

\left\{\begin{array}{l}25x+10y=400\\y=x+5\end{array}\right..

Substitute second equation into the first one:

25x+10(x+5)=400,\\ \\25x+10x+50=400,\\ \\35x=350,\\ \\x=10,\ y=10+5=15.

10 quaters and 15 dimes

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Prove Forall x elementof Z, x^2 - 5x - 1 is odd.
Diano4ka-milaya [45]

Answer with Step-by-step explanation:

Let Z be a set of integers

We have to prove that x^2-5x-1 is odd for all value of x \inZ.

There are two cases

1.When x is an odd integer number

2.when x is even integer number

1.When x is an odd integer  number

When x is positive odd integer

Then x^2  is positive odd number (because square of odd positive number is always positive an odd number )

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-5x -1 = -even number

Suppose x=3

Then -15-1=-16

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Hence ,x^2-5x-1 is an odd number .

When x is negative odd number

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Therefore,odd number + odd number -1=Even  number -1=Odd number

Hence x^2-5x-1 is an odd number.

2.When  x is an even number

When x is positive even number

x square is positive even number  and 5x is positive even number

Even number -Even number -1 =Even number -odd number =Odd number

Suppose x=4

x^2-5x-1=16-20-1=-5=Odd number

When x is negative even number

Then x square is positive even number  and 5x is negative even number

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Hence, for all elements of Zx^2-5x-1is odd.

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2 years ago
A 500 g model train car traveling at 0.8 m/s collides with a 300 g stationary car. The cars hook up and move off down the track
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Answer:

0.5ms^{-1}

Step-by-step explanation:

Let v be the speed after the collision of both the cars.

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⇒400=800v

⇒v=0.5ms^{-1}

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3 years ago
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